Sure! Let's analyze each circuit step-by-step to determine if they correctly follow Ohm's Law, which states that [tex]\( V = I \times R \)[/tex]. We'll look at each given voltage (V), current (I), and resistance (R) combination to see if the relation holds true.
### Circuit 1
- Voltage (V): 25V
- Current (I): 5A
- Resistance (R): 5 ohms
Using Ohm's Law:
[tex]\[ V = I \times R \][/tex]
[tex]\[ 25 = 5 \times 5 \][/tex]
[tex]\[ 25 = 25 \][/tex]
This circuit follows Ohm's Law.
### Circuit 2
- Voltage (V): 56V
- Current (I): 7A
- Resistance (R): 5 ohms
Using Ohm's Law:
[tex]\[ V = I \times R \][/tex]
[tex]\[ 56 = 7 \times 5 \][/tex]
[tex]\[ 56 = 35 \][/tex]
This circuit does NOT follow Ohm's Law.
### Circuit 3
- Voltage (V): 18V
- Current (I): 5A
- Resistance (R): 8 ohms
Using Ohm's Law:
[tex]\[ V = I \times R \][/tex]
[tex]\[ 18 = 5 \times 8 \][/tex]
[tex]\[ 18 = 40 \][/tex]
This circuit does NOT follow Ohm's Law.
### Circuit 4
- Voltage (V): 20V
- Current (I): 6A
- Resistance (R): 4 ohms
Using Ohm's Law:
[tex]\[ V = I \times R \][/tex]
[tex]\[ 20 = 6 \times 4 \][/tex]
[tex]\[ 20 = 24 \][/tex]
This circuit does NOT follow Ohm's Law.
### Summary
From our analysis, the only circuit that correctly shows Ohm's Law is Circuit 1.
