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A salesperson earns [tex]$\$[/tex] 200[tex]$ a week plus a $[/tex]4 \%[tex]$ commission on her sales. Which equation models the relationship between her sales in a given week, $[/tex]s[tex]$, and her weekly earnings, $[/tex]e[tex]$?

A. $[/tex]e=\frac{200 s+4}{100}[tex]$
B. $[/tex]e=200 s+4[tex]$
C. $[/tex]e=4 s+200[tex]$
D. $[/tex]e=\frac{4}{100} s+200$

Sagot :

To determine the equation that models the relationship between the sales in a given week, [tex]\( s \)[/tex], and the weekly earnings, [tex]\( e \)[/tex], we need to take into account the two components of the salesperson's earnings:

1. A base salary of $200 per week.
2. A commission of [tex]\( 4\% \)[/tex] on the sales, [tex]\( s \)[/tex].

First, let's convert the percentage commission into a decimal for ease of calculation:
[tex]\[ 4\% = \frac{4}{100} = 0.04 \][/tex]

Now we can write the total earnings, [tex]\( e \)[/tex], as the sum of the base salary and the sales commission.

The commission part of the earnings is:
[tex]\[ \text{Commission} = 0.04s \][/tex]

So the total weekly earnings, [tex]\( e \)[/tex], can be expressed as:
[tex]\[ e = 200 + 0.04s \][/tex]

Now, let's compare this equation with the given options:

1. [tex]\( e = \frac{200s + 4}{100} \)[/tex]

Simplifying this equation:
[tex]\[ \frac{200s + 4}{100} = 2s + 0.04 \][/tex]
This does not match our derived equation.

2. [tex]\( e = 200s + 4 \)[/tex]

This equation indicates that the earnings are proportional to the sales plus an arbitrary constant addition, which does not match our derived form.

3. [tex]\( e = 4s + 200 \)[/tex]

This equation indicates that the commission rate is much higher than 4%, which is not in accordance with the given problem.

4. [tex]\( e = \frac{4}{100}s + 200 \)[/tex]

Simplifying this equation:
[tex]\[ \frac{4}{100}s = 0.04s \][/tex]
Therefore,
[tex]\[ e = 0.04s + 200 \][/tex]
This matches our derived equation exactly.

Hence, the correct equation that models the relationship between the salesperson's sales and weekly earnings is:
[tex]\[ e = \frac{4}{100}s + 200 \][/tex]