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Fifty-eight more than the second of three consecutive even integers is the same as the diffrence between the third and ten times the first. Find the numbers

Sagot :

Answer:

Step-by-step explanation:

To solve this problem, let's first define the three consecutive even integers as x, x+2, and x+4.

According to the given information, fifty-eight more than the second integer (x+2) is equal to the difference between the third integer (x+4) and ten times the first integer (10x).

Mathematically, we can represent this as:

(x+2) + 58 = (x+4) - 10x

Solving this equation step by step:

x + 2 + 58 = x + 4 - 10x

x + 60 = 4 - 9x

60 = -5x

x = -12

Now that we have found the value of the first integer x, we can calculate the other two consecutive even integers:

First integer: x = -12

Second integer: x + 2 = -12 + 2 = -10

Third integer: x + 4 = -12 + 4 = -8

Therefore, the three consecutive even integers are -12, -10, and -8.

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