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Find the area of a square whose perimeter is [tex]$9 \frac{1}{11} \text{ m}$[/tex].

Sagot :

To find the area of a square given its perimeter, let's proceed step-by-step.

1. Understanding the Perimeter:
The given perimeter of the square is [tex]\(9 \frac{1}{11} \text{ meters}\)[/tex]. First, we convert this mixed number into an improper fraction for simplicity in our calculations:
[tex]\[ 9 \frac{1}{11} = \frac{9 \times 11 + 1}{11} = \frac{99 + 1}{11} = \frac{100}{11} \text{ meters} \][/tex]

2. Finding the Side Length:
The perimeter of a square is calculated as four times its side length. Let [tex]\( s \)[/tex] be the side length of the square.
[tex]\[ 4s = \frac{100}{11} \][/tex]
To find [tex]\( s \)[/tex], we divide both sides of the equation by 4:
[tex]\[ s = \frac{100}{11} \div 4 = \frac{100}{11} \times \frac{1}{4} = \frac{100}{44} = \frac{25}{11} \text{ meters} \][/tex]

3. Calculating the Area:
The area [tex]\(A\)[/tex] of a square is given by the square of its side length:
[tex]\[ A = s^2 \][/tex]
Substituting the value of [tex]\( s \)[/tex]:
[tex]\[ A = \left(\frac{25}{11}\right)^2 = \frac{25 \times 25}{11 \times 11} = \frac{625}{121} \text{ square meters} \][/tex]

Converting [tex]\(\frac{625}{121}\)[/tex] to a decimal, we get:
[tex]\[ \frac{625}{121} \approx 5.165289256198348 \text{ square meters} \][/tex]

4. Conclusion:
Therefore, the area of the square is approximately [tex]\(\boxed{5.165289256198348 \text{ square meters}}\)[/tex].

In summary:
- Side length: [tex]\( \approx 2.272727272727273 \text{ meters} \)[/tex]
- Area: [tex]\( \approx 5.165289256198348 \text{ square meters} \)[/tex]