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Simplify the expression below:
[tex]\[ \left(\frac{2n}{6n+4}\right)\left(\frac{3n+2}{3n-2}\right) \][/tex]

What is the numerator of the simplified expression?

A. 2
B. n
C. [tex]\(3n - 2\)[/tex]
D. [tex]\(3n + 2\)[/tex]


Sagot :

To simplify the given expression, let's break it down step-by-step:

The expression is:
[tex]\[ \left( \frac{2n}{6n+4} \right) \left( \frac{3n+2}{3n-2} \right) \][/tex]

1. Factor the denominators and numerators where possible:
- In the fraction [tex]\(\frac{2n}{6n + 4}\)[/tex], notice that [tex]\(6n + 4\)[/tex] can be factored:
[tex]\[ 6n + 4 = 2(3n + 2) \][/tex]
So, the fraction becomes:
[tex]\[ \frac{2n}{2(3n + 2)} \][/tex]

2. Simplify the expression:
- We can cancel the common factor of 2 in the numerator and the denominator:
[tex]\[ \frac{2n}{2(3n + 2)} = \frac{n}{3n + 2} \][/tex]

3. Now, let's multiply the simplified fraction with the second fraction:
[tex]\[ \left( \frac{n}{3n + 2} \right) \left( \frac{3n + 2}{3n - 2} \right) \][/tex]

4. Simplify the product:
- Notice that [tex]\((3n + 2)\)[/tex] in the numerator and the denominator will cancel out:
[tex]\[ \frac{n}{3n + 2} \cdot \frac{3n + 2}{3n - 2} = \frac{n \cdot (3n + 2)}{(3n + 2) \cdot (3n - 2)} \][/tex]
- This can be simplified further as:
[tex]\[ \frac{n}{3n - 2} \][/tex]

However, based on the calculations provided, it is clear that the numerator of the simplified expression directly turns out to be:
[tex]\[ n \][/tex]

Thus, the numerator of the simplified expression is:
[tex]\[ \boxed{n} \][/tex]