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Given the function [tex]f(x) = 4x + 2[/tex], find [tex]f(0)[/tex].

Sagot :

To solve for [tex]\( f(0) \)[/tex] when the function is given by [tex]\( f(x) = 4x + 2 \)[/tex], follow these steps:

1. Identify the function and the input value:
- The function given is [tex]\( f(x) = 4x + 2 \)[/tex].
- We need to find the value of the function when [tex]\( x = 0 \)[/tex].

2. Substitute the input value into the function:
- Replace [tex]\( x \)[/tex] with [tex]\( 0 \)[/tex] in the function [tex]\( f(x) \)[/tex].

3. Perform the substitution:
- [tex]\( f(0) = 4(0) + 2 \)[/tex].

4. Simplify the expression:
- Calculate [tex]\( 4 \times 0 \)[/tex].
- [tex]\( 4 \times 0 = 0 \)[/tex].
- Then add [tex]\( 2 \)[/tex].
- [tex]\( 0 + 2 = 2 \)[/tex].

5. State the result:
- [tex]\( f(0) = 2 \)[/tex].

Hence, the value of [tex]\( f(0) \)[/tex] is [tex]\( 2 \)[/tex].