Sure, let's find the conjugate base of [tex]\( HSO_4^- \)[/tex] step by step.
1. Understanding the Conjugate Base Concept:
- The conjugate base of an acid is formed by removing one proton (H[tex]\(^+\)[/tex]) from the acid.
2. Given Information:
- The acid provided is [tex]\( HSO_4^- \)[/tex].
3. Removing a Proton:
- To find the conjugate base, we need to remove one proton from [tex]\( HSO_4^- \)[/tex].
4. Formula Transformation:
- When you remove an H[tex]\(^+\)[/tex] (proton) from [tex]\( HSO_4^- \)[/tex], you are left with [tex]\( SO_4^{2-} \)[/tex].
5. Result:
- Therefore, the conjugate base of [tex]\( HSO_4^- \)[/tex] is [tex]\( SO_4^{2-} \)[/tex].
So, the formula of the conjugate base of [tex]\( HSO_4^- \)[/tex] is:
[tex]\[
\text{conjugate base:} \quad SO_4^{2-}
\][/tex]
