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Working together, Rocco and Giulia can paint a room in 3 hours. It would have taken Rocco 7 hours to do the job alone. Which equation can be used to determine [tex]\( r \)[/tex], Giulia's rate of work in parts per hour?

[tex]\[
\begin{tabular}{|c|c|c|c|}
\hline
& \begin{tabular}{c}
Rate \\ (part/hour)
\end{tabular}
& \begin{tabular}{c}
Time \\ (hours)
\end{tabular}
& \begin{tabular}{c}
Part of \\ Room \\ Painted
\end{tabular} \\
\hline
Rocco & \(\frac{1}{7}\) & 3 & \(\frac{3}{7}\) \\
\hline
Giulia & \(r\) & 3 & \(3r\) \\
\hline
\end{tabular}
\][/tex]

A. [tex]\(\frac{3}{7} + 3r = 7\)[/tex]
B. [tex]\(\frac{3}{7} + 3r = 1\)[/tex]
C. [tex]\(\frac{1}{7} = 1\)[/tex]
D. [tex]\(\frac{3}{7} = 3r\)[/tex]

Sagot :

To find the correct equation involving Giulia's rate of work [tex]\( r \)[/tex] in parts per hour, let's break down the problem step-by-step.

1. Rocco's Rate of Work:
- Rocco can paint the room alone in 7 hours.
- Therefore, Rocco's rate of work is [tex]\(\frac{1}{7}\)[/tex] parts per hour.

2. Time Taken Together:
- Rocco and Giulia, working together, can paint the room in 3 hours.

3. Contribution of Work when Working Together:
- Together they paint one entire room (which can be considered as 1 part) in 3 hours.
- Thus, the combined rate of Rocco and Giulia is [tex]\(\frac{1}{3}\)[/tex] rooms per hour.

4. Rocco's Contribution:
- Rocco's rate is [tex]\(\frac{1}{7}\)[/tex] parts per hour, so in 3 hours, he paints [tex]\(3 \times \frac{1}{7} = \frac{3}{7}\)[/tex] of the room.

5. Giulia's Contribution:
- Let [tex]\( r \)[/tex] be Giulia's rate of work in parts per hour.
- In 3 hours, Giulia would paint [tex]\( 3r \)[/tex] parts of the room.

6. Total Work Done:
- The total work done by Rocco and Giulia together in 3 hours should be 1 entire room.
- Therefore, [tex]\( \frac{3}{7} + 3r = 1 \)[/tex].

7. Equation for Giulia's Rate of Work:
- Hence, the equation we can use to determine [tex]\( r \)[/tex] is:
[tex]\[ \frac{3}{7} + 3r = 1 \][/tex]

Thus, the equation to determine [tex]\( r \)[/tex], Giulia's rate of work in parts per hour, is:
[tex]\[ \boxed{\frac{3}{7} + 3r = 1} \][/tex]