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Sagot :
To determine how long it takes for a car traveling at a speed of 35 meters per second to cover a distance of 100 meters, we can use the relationship between distance, speed, and time given by the equation:
[tex]\[ d = s \cdot t \][/tex]
Here, [tex]\( d \)[/tex] is the distance, [tex]\( s \)[/tex] is the speed, and [tex]\( t \)[/tex] is the time. We need to solve for [tex]\( t \)[/tex]. Rearrange the equation to solve for time [tex]\( t \)[/tex]:
[tex]\[ t = \frac{d}{s} \][/tex]
Now, let's substitute the given values into the equation:
- The speed [tex]\( s \)[/tex] is 35 meters per second.
- The distance [tex]\( d \)[/tex] is 100 meters.
Thus,
[tex]\[ t = \frac{100 \text{ m}}{35 \text{ m/s}} \][/tex]
When we divide 100 by 35, we get:
[tex]\[ t \approx 2.857142857142857 \text{ seconds} \][/tex]
Rounding to one decimal place, the time [tex]\( t \)[/tex] is approximately 2.9 seconds. Therefore, the correct answer is:
D. 2.9 s
[tex]\[ d = s \cdot t \][/tex]
Here, [tex]\( d \)[/tex] is the distance, [tex]\( s \)[/tex] is the speed, and [tex]\( t \)[/tex] is the time. We need to solve for [tex]\( t \)[/tex]. Rearrange the equation to solve for time [tex]\( t \)[/tex]:
[tex]\[ t = \frac{d}{s} \][/tex]
Now, let's substitute the given values into the equation:
- The speed [tex]\( s \)[/tex] is 35 meters per second.
- The distance [tex]\( d \)[/tex] is 100 meters.
Thus,
[tex]\[ t = \frac{100 \text{ m}}{35 \text{ m/s}} \][/tex]
When we divide 100 by 35, we get:
[tex]\[ t \approx 2.857142857142857 \text{ seconds} \][/tex]
Rounding to one decimal place, the time [tex]\( t \)[/tex] is approximately 2.9 seconds. Therefore, the correct answer is:
D. 2.9 s
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