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The table summarizes results from 980 pedestrian deaths that were caused by automobile accidents.

[tex]\[
\begin{tabular}{|c|c|c|}
\hline
\begin{tabular}{c}
Driver \\
Intoxicated?
\end{tabular} & \multicolumn{2}{|c|}{ Pedestrian Intoxicated? } \\
\cline{2-3} & Yes & No \\
\hline Yes & 64 & 66 \\
\hline No & 234 & 616 \\
\hline
\end{tabular}
\][/tex]

If one of the pedestrian deaths is randomly selected, find the probability that neither the pedestrian nor the driver was intoxicated. Please enter a decimal to 4 places.

[tex]\[
\text{Probability} = \square
\][/tex]

Sagot :

To solve the problem of finding the probability that neither the pedestrian nor the driver was intoxicated, follow these steps:

1. Identify the Total Number of Cases:
According to the table, the total number of pedestrian deaths caused by automobile accidents is 980.

2. Identify the Number of Favorable Cases:
We need to find the number of cases where neither the pedestrian nor the driver was intoxicated. From the table, the number of such cases is found in the cell corresponding to "Driver Not Intoxicated" and "Pedestrian Not Intoxicated", which is 616.

3. Calculate the Probability:
The probability of an event is defined as the number of favorable outcomes divided by the total number of outcomes. In this case, the probability [tex]\(P\)[/tex] that neither the pedestrian nor the driver was intoxicated is given by:
[tex]\[ P = \frac{\text{Number of favorable cases}}{\text{Total number of cases}} \][/tex]

4. Substitute the Values:
Substituting the numbers we have:
[tex]\[ P = \frac{616}{980} \][/tex]

5. Convert to Decimal Form:
Simplifying the fraction to a decimal value up to 4 places, we get:
[tex]\[ P \approx 0.6286 \][/tex]

Therefore, the probability that neither the pedestrian nor the driver was intoxicated is approximately 0.6286.