Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Get quick and reliable solutions to your questions from knowledgeable professionals on our comprehensive Q&A platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
To determine the mass of helium in the blimp, let's follow a series of steps:
1. Conversion of Volume:
- We need to convert the given volume in milliliters to cubic meters. Given, the volume of helium is [tex]\(6.28 \times 10^9 \)[/tex] milliliters.
- We know that [tex]\(1,000 L = 1\)[/tex] cubic meter. Hence, [tex]\(1 \text{ milliL} = 1 \times 10^{-6} \text{ cubic meters}\)[/tex].
- Therefore, [tex]\(6.28 \times 10^9\)[/tex] milliliters is equal to [tex]\(6.28 \times 10^9 \times 10^{-6}\)[/tex] cubic meters.
- Simplifying this, we get:
[tex]\[ 6.28 \times 10^9 \times 10^{-6} = 6.28 \times 10^3 = 6280 \text{ cubic meters} \][/tex]
2. Compute the Mass:
- The density of helium is given as [tex]\(0.1786 \frac{\text{ kilogram}}{\text{ cubic meter }}\)[/tex].
- Mass can be calculated using the formula:
[tex]\[ \text{Mass} = \text{Density} \times \text{Volume} \][/tex]
- Substituting the values we have:
[tex]\[ \text{Mass} = 0.1786 \frac{\text{ kg}}{\text{ m}^3} \times 6280 \text{ m}^3 = 1121.608 \text{ kilograms} \][/tex]
Comparing the computed mass with the given options, we find:
A. [tex]\(1,120 \text{ kg}\)[/tex] (This is the correct answer considering minor rounding)
B. [tex]\(1.12 \text{ kg}\)[/tex] (Incorrect, too low)
C. [tex]\(3.52 \times 10^7 \text{ kg}\)[/tex] (Incorrect, too high)
D. [tex]\(2,840 \text{ kg}\)[/tex] (Incorrect, too high)
Therefore, the correct answer is:
A. 1,120 kg
1. Conversion of Volume:
- We need to convert the given volume in milliliters to cubic meters. Given, the volume of helium is [tex]\(6.28 \times 10^9 \)[/tex] milliliters.
- We know that [tex]\(1,000 L = 1\)[/tex] cubic meter. Hence, [tex]\(1 \text{ milliL} = 1 \times 10^{-6} \text{ cubic meters}\)[/tex].
- Therefore, [tex]\(6.28 \times 10^9\)[/tex] milliliters is equal to [tex]\(6.28 \times 10^9 \times 10^{-6}\)[/tex] cubic meters.
- Simplifying this, we get:
[tex]\[ 6.28 \times 10^9 \times 10^{-6} = 6.28 \times 10^3 = 6280 \text{ cubic meters} \][/tex]
2. Compute the Mass:
- The density of helium is given as [tex]\(0.1786 \frac{\text{ kilogram}}{\text{ cubic meter }}\)[/tex].
- Mass can be calculated using the formula:
[tex]\[ \text{Mass} = \text{Density} \times \text{Volume} \][/tex]
- Substituting the values we have:
[tex]\[ \text{Mass} = 0.1786 \frac{\text{ kg}}{\text{ m}^3} \times 6280 \text{ m}^3 = 1121.608 \text{ kilograms} \][/tex]
Comparing the computed mass with the given options, we find:
A. [tex]\(1,120 \text{ kg}\)[/tex] (This is the correct answer considering minor rounding)
B. [tex]\(1.12 \text{ kg}\)[/tex] (Incorrect, too low)
C. [tex]\(3.52 \times 10^7 \text{ kg}\)[/tex] (Incorrect, too high)
D. [tex]\(2,840 \text{ kg}\)[/tex] (Incorrect, too high)
Therefore, the correct answer is:
A. 1,120 kg
Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.