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write the equation of line that passing through (3,0),(6,3)

Sagot :

Answer:

Step-by-step explanation:

To find the equation of the line passing through the points \((3,0)\) and \((6,3)\), we can follow these steps:

1. **Calculate the slope (\(m\)) of the line** using the formula:

  \[

  m = \frac{y_2 - y_1}{x_2 - x_1}

  \]

  Substitute \((x_1, y_1) = (3, 0)\) and \((x_2, y_2) = (6, 3)\):

  \[

  m = \frac{3 - 0}{6 - 3} = \frac{3}{3} = 1

  \]

2. **Use the point-slope form of the equation of a line**, which is:

  \[

  y - y_1 = m(x - x_1)

  \]

  Choose either point to substitute into the equation. Let's use \((3, 0)\) and \(m = 1\):

  \[

  y - 0 = 1(x - 3)

  \]

  Simplify the equation:

  \[

  y = x - 3

  \]

3. **Verify the solution** by substituting the other point \((6, 3)\) into the equation to ensure it satisfies the line:

  \[

  y = 6 - 3 = 3

  \]

  Since \(y = 3\) when \(x = 6\), the point \((6, 3)\) lies on the line.

Therefore, the equation of the line passing through the points \((3,0)\) and \((6,3)\) is \( \boxed{y = x - 3} \).