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Sagot :
o evaluate the expression
6
⋅
2
6⋅2x for the given values of
x:Answer:
Step-by-step explanation:
(a) For
=
−
2
x=−2:
6
⋅
2
=
6
⋅
2
(
−
2
)
6⋅2x=6⋅2(−2)
Calculate inside the parentheses first:
6
⋅
2
(
−
2
)
=
6
⋅
(
−
4
)
6⋅2(−2)=6⋅(−4)
Now, perform the multiplication:
6
⋅
(
−
4
)
=
−
24
6⋅(−4)=−24
So,
6
⋅
2
6⋅2x when
=
−
2
x=−2 is
−
24
−24
.
(b) For
=
3
x=3:
6
⋅
2
=
6
⋅
2
(
3
)
6⋅2x=6⋅2(3)
Calculate inside the parentheses first:
6
⋅
2
(
3
)
=
6
⋅
6
6⋅2(3)=6⋅6
Now, perform the multiplication:
6
⋅
6
=
36
6⋅6=36
So,
6
⋅
2
6⋅2x when
=
3
x=3 is
36
36
.
Therefore, the evaluated expressions are
−
24
−24
when
=
−
2
x=−2 and
36
36
when
=
3
x=3.
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