Westonci.ca is the ultimate Q&A platform, offering detailed and reliable answers from a knowledgeable community. Join our platform to get reliable answers to your questions from a knowledgeable community of experts. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
To determine the magnitude of force required to accelerate a car with a mass of [tex]\(1.7 \times 10^3\)[/tex] kilograms at an acceleration of [tex]\(4.75\)[/tex] meters per second squared, we can use Newton's second law of motion, which is formulated as:
[tex]\[ F = m \times a \][/tex]
where:
- [tex]\( F \)[/tex] is the force,
- [tex]\( m \)[/tex] is the mass,
- [tex]\( a \)[/tex] is the acceleration.
Given:
- [tex]\( m = 1.7 \times 10^3 \)[/tex] kg,
- [tex]\( a = 4.75 \)[/tex] m/s²,
we substitute the values into the formula:
[tex]\[ F = (1.7 \times 10^3 \, \text{kg}) \times 4.75 \, \text{m/s}^2 \][/tex]
By multiplying these values, we find:
[tex]\[ F = 1.7 \times 4.75 \times 10^3 \, \text{N} \][/tex]
[tex]\[ F = 8.075 \times 10^3 \, \text{N} \][/tex]
Therefore, the magnitude of the force required to accelerate the car is [tex]\( 8075.0 \)[/tex] newtons, which corresponds to one of the provided options:
C. [tex]\( 8.1 \times 10^3 \)[/tex] newtons
Thus, the correct answer is:
[tex]\[ \boxed{8.1 \times 10^3 \, \text{newtons}} \][/tex]
[tex]\[ F = m \times a \][/tex]
where:
- [tex]\( F \)[/tex] is the force,
- [tex]\( m \)[/tex] is the mass,
- [tex]\( a \)[/tex] is the acceleration.
Given:
- [tex]\( m = 1.7 \times 10^3 \)[/tex] kg,
- [tex]\( a = 4.75 \)[/tex] m/s²,
we substitute the values into the formula:
[tex]\[ F = (1.7 \times 10^3 \, \text{kg}) \times 4.75 \, \text{m/s}^2 \][/tex]
By multiplying these values, we find:
[tex]\[ F = 1.7 \times 4.75 \times 10^3 \, \text{N} \][/tex]
[tex]\[ F = 8.075 \times 10^3 \, \text{N} \][/tex]
Therefore, the magnitude of the force required to accelerate the car is [tex]\( 8075.0 \)[/tex] newtons, which corresponds to one of the provided options:
C. [tex]\( 8.1 \times 10^3 \)[/tex] newtons
Thus, the correct answer is:
[tex]\[ \boxed{8.1 \times 10^3 \, \text{newtons}} \][/tex]
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.