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[tex]$ \$[/tex] 96[tex]$ is eight times as much money as Al had. How much did Al have? Select the correct solution method below, representing it with $[/tex]x[tex]$.

A. $[/tex]x-8=96[tex]$. Add 8 to both sides. Al had $[/tex]\[tex]$ 104$[/tex].

B. [tex]$8x=96$[/tex]. Divide both sides by 8. Al had [tex]$\$[/tex] 12[tex]$.

C. $[/tex]\frac{x}{8}=96[tex]$. Multiply both sides by 8. Al had $[/tex]\[tex]$ 768$[/tex].

D. [tex]$x+8=96$[/tex]. Subtract 8 from both sides. Al had [tex]$\$[/tex] 88$.

Sagot :

GinnyAnswer
Let's carefully solve the problem step-by-step:

We are given that [tex]$96$[/tex] dollars is eight times the amount of money Al had. We need to find out how much money Al had.

Let [tex]$x$[/tex] represent the amount of money Al had.

The equation representing the situation is:
[tex]\[8x = 96\][/tex]

To solve for [tex]$x$[/tex], we need to isolate [tex]$x$[/tex] on one side of the equation. We do this by dividing both sides of the equation by [tex]$8$[/tex]:

[tex]\[ x = \frac{96}{8} \][/tex]

When we perform the division:

[tex]\[ x = 12 \][/tex]

Therefore, Al had [tex]$\$[/tex]12[tex]$. The correct method to solve this problem is: \[8x = 96\] Divide both sides by $[/tex]8[tex]$. \[x = 12\] Al had $[/tex]\[tex]$ 12$[/tex].
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