Westonci.ca makes finding answers easy, with a community of experts ready to provide you with the information you seek. Discover a wealth of knowledge from professionals across various disciplines on our user-friendly Q&A platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

1. Problem-solving:
Calculate the molarity of a solution made by dissolving 10 grams of [tex]\(K_2CO_3\)[/tex] in enough water to make 300 mL of solution. (Molar mass of [tex]\(K_2CO_3 = 138.2 \, g/mol\)[/tex]).


Sagot :

To calculate the molarity of a solution, follow these steps:

1. Identify the given values:
- Mass of solute (solute here is [tex]\(K_2O_3\)[/tex]): 10 grams
- Volume of the solution: 300 milliliters
- Molar mass of the solute ([tex]\(CNO_3\)[/tex]): 101.1 grams per mole

2. Convert the volume of solution to liters:
- Volume in liters = Volume in milliliters / 1000
- Volume in liters = 300 ml / 1000
- Volume in liters = 0.3 liters

3. Calculate the number of moles of solute:
- Moles of solute = Mass of solute / Molar mass of solute
- Moles of solute = 10 grams / 101.1 grams per mole
- Moles of solute ≈ 0.09891196834817013 moles

4. Calculate the molarity of the solution:
- Molarity (M) = Moles of solute / Volume of solution in liters
- Molarity (M) = 0.09891196834817013 moles / 0.3 liters
- Molarity (M) ≈ 0.3297065611605671 M

Therefore, the molarity of the solution is approximately 0.3297 M.
We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We appreciate your time. Please come back anytime for the latest information and answers to your questions. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.