Explore Westonci.ca, the premier Q&A site that helps you find precise answers to your questions, no matter the topic. Experience the ease of finding reliable answers to your questions from a vast community of knowledgeable experts. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.
Sagot :
To solve this problem, follow these steps:
1. Matrix [tex]\( A \)[/tex] Representation:
We need to work with the matrix [tex]\( A \)[/tex]:
[tex]\[ A = \left[\begin{array}{ccc} 1 & 2 & -4 \\ 0 & 3 & -1 \end{array}\right] \][/tex]
2. Scaling the Matrix [tex]\( A \)[/tex] by 4:
To compute [tex]\( 4A \)[/tex], we multiply each element of the matrix [tex]\( A \)[/tex] by 4. So, we calculate each element as follows:
[tex]\[ 4A = 4 \times \left[\begin{array}{ccc} 1 & 2 & -4 \\ 0 & 3 & -1 \end{array}\right] = \left[\begin{array}{ccc} 4 \times 1 & 4 \times 2 & 4 \times -4 \\ 4 \times 0 & 4 \times 3 & 4 \times -1 \end{array}\right] \][/tex]
Performing the multiplications:
[tex]\[ 4A = \left[\begin{array}{ccc} 4 & 8 & -16 \\ 0 & 12 & -4 \end{array}\right] \][/tex]
3. Extracting the Particular Element:
We are asked to find the element in row 2, column 3 of the matrix [tex]\( 4A \)[/tex]. From the matrix computed:
[tex]\[ 4A = \left[\begin{array}{ccc} 4 & 8 & -16 \\ 0 & 12 & -4 \end{array}\right] \][/tex]
Look at the second row:
[tex]\[ \left[0, 12, -4\right] \][/tex]
The element in column 3 of this row is [tex]\( -4 \)[/tex].
So, the element in row 2, column 3 of [tex]\( 4A \)[/tex] is:
[tex]\[ -4 \][/tex]
1. Matrix [tex]\( A \)[/tex] Representation:
We need to work with the matrix [tex]\( A \)[/tex]:
[tex]\[ A = \left[\begin{array}{ccc} 1 & 2 & -4 \\ 0 & 3 & -1 \end{array}\right] \][/tex]
2. Scaling the Matrix [tex]\( A \)[/tex] by 4:
To compute [tex]\( 4A \)[/tex], we multiply each element of the matrix [tex]\( A \)[/tex] by 4. So, we calculate each element as follows:
[tex]\[ 4A = 4 \times \left[\begin{array}{ccc} 1 & 2 & -4 \\ 0 & 3 & -1 \end{array}\right] = \left[\begin{array}{ccc} 4 \times 1 & 4 \times 2 & 4 \times -4 \\ 4 \times 0 & 4 \times 3 & 4 \times -1 \end{array}\right] \][/tex]
Performing the multiplications:
[tex]\[ 4A = \left[\begin{array}{ccc} 4 & 8 & -16 \\ 0 & 12 & -4 \end{array}\right] \][/tex]
3. Extracting the Particular Element:
We are asked to find the element in row 2, column 3 of the matrix [tex]\( 4A \)[/tex]. From the matrix computed:
[tex]\[ 4A = \left[\begin{array}{ccc} 4 & 8 & -16 \\ 0 & 12 & -4 \end{array}\right] \][/tex]
Look at the second row:
[tex]\[ \left[0, 12, -4\right] \][/tex]
The element in column 3 of this row is [tex]\( -4 \)[/tex].
So, the element in row 2, column 3 of [tex]\( 4A \)[/tex] is:
[tex]\[ -4 \][/tex]
Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.