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How many Cobbert atoms are in a 345 g of Cobbert

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To determine the number of Cobbert atoms in 345 g of Cobbert, we need to first calculate the number of moles of Cobbert in 345 g using the molar mass of Cobbert.

The molar mass of Cobbert (CoBr) = atomic mass of Cobalt (Co) + atomic mass of Bromine (Br)

= 58.9332 g/mol + 79.904 g/mol

= 138.8372 g/mol

Number of moles = mass / molar mass

Number of moles = 345 g / 138.8372 g/mol = 2.483 moles

Now, to find the number of Cobbert atoms in 2.483 moles, we use Avogadro's number:

1 mole of any substance contains Avogadro's number of particles (6.022 x 10^23)

Number of Cobbert atoms = number of moles x Avogadro's number

Number of Cobbert atoms = 2.483 moles x 6.022 x 10^23 atoms/mol = 1.495 x 10^24 Cobbert atoms

Therefore, there are approximately 1.495 x 10^24 Cobbert atoms in 345 g of Cobbert.

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