Discover answers to your most pressing questions at Westonci.ca, the ultimate Q&A platform that connects you with expert solutions. Explore a wealth of knowledge from professionals across various disciplines on our comprehensive Q&A platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
To determine how high the table is lifted, we can use the formula for gravitational potential energy. The formula is:
[tex]\[ P.E. = m \cdot g \cdot h \][/tex]
where:
- [tex]\( P.E. \)[/tex] is the gravitational potential energy
- [tex]\( m \)[/tex] is the mass of the object
- [tex]\( g \)[/tex] is the acceleration due to gravity
- [tex]\( h \)[/tex] is the height
Given:
- The mass of the table ([tex]\( m \)[/tex]) is [tex]\( 10 \, \text{kg} \)[/tex]
- The increase in gravitational potential energy ([tex]\( P.E. \)[/tex]) is [tex]\( 1470 \, \text{J} \)[/tex]
- The acceleration due to gravity ([tex]\( g \)[/tex]) is [tex]\( 9.8 \, \text{m/s}^2 \)[/tex]
We need to find the height ([tex]\( h \)[/tex]) to which the table is lifted. Rearranging the formula to solve for [tex]\( h \)[/tex] gives:
[tex]\[ h = \frac{P.E.}{m \cdot g} \][/tex]
Substituting the given values into this equation:
[tex]\[ h = \frac{1470 \, \text{J}}{10 \, \text{kg} \cdot 9.8 \, \text{m/s}^2} \][/tex]
[tex]\[ h = \frac{1470}{98} \][/tex]
[tex]\[ h = 15 \, \text{m} \][/tex]
Therefore, the table is lifted to a height of [tex]\( 15 \)[/tex] meters. The correct answer is:
D. 15 m
[tex]\[ P.E. = m \cdot g \cdot h \][/tex]
where:
- [tex]\( P.E. \)[/tex] is the gravitational potential energy
- [tex]\( m \)[/tex] is the mass of the object
- [tex]\( g \)[/tex] is the acceleration due to gravity
- [tex]\( h \)[/tex] is the height
Given:
- The mass of the table ([tex]\( m \)[/tex]) is [tex]\( 10 \, \text{kg} \)[/tex]
- The increase in gravitational potential energy ([tex]\( P.E. \)[/tex]) is [tex]\( 1470 \, \text{J} \)[/tex]
- The acceleration due to gravity ([tex]\( g \)[/tex]) is [tex]\( 9.8 \, \text{m/s}^2 \)[/tex]
We need to find the height ([tex]\( h \)[/tex]) to which the table is lifted. Rearranging the formula to solve for [tex]\( h \)[/tex] gives:
[tex]\[ h = \frac{P.E.}{m \cdot g} \][/tex]
Substituting the given values into this equation:
[tex]\[ h = \frac{1470 \, \text{J}}{10 \, \text{kg} \cdot 9.8 \, \text{m/s}^2} \][/tex]
[tex]\[ h = \frac{1470}{98} \][/tex]
[tex]\[ h = 15 \, \text{m} \][/tex]
Therefore, the table is lifted to a height of [tex]\( 15 \)[/tex] meters. The correct answer is:
D. 15 m
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.