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A supervisor finds the mean number of miles that the employees in a department live from work. He finds [tex]\bar{x}=29[/tex] and [tex]s=3.6[/tex]. Which mileage is within a [tex]z[/tex]-score of -1.5?

A. 21 miles
B. 24 miles
C. 36 miles
D. 41 miles


Sagot :

To determine which mileage corresponds to a [tex]$z$[/tex]-score of -1.5, we need to use the formula that relates the [tex]$z$[/tex]-score to a specific data point within a normally distributed set of data. The formula for the [tex]$z$[/tex]-score is given by:

[tex]\[ z = \frac{x - \bar{x}}{s} \][/tex]

where:
- [tex]\( x \)[/tex] is the value we are trying to find (in this case, the mileage corresponding to a [tex]$z$[/tex]-score of -1.5),
- [tex]\( \bar{x} \)[/tex] is the mean of the data (which is 29 miles),
- [tex]\( s \)[/tex] is the standard deviation of the data (which is 3.6 miles).

Let's rearrange the formula to solve for [tex]\( x \)[/tex]:

[tex]\[ x = \bar{x} + z \cdot s \][/tex]

Now, plug in the given values:

- [tex]\(\bar{x} = 29\)[/tex]
- [tex]\(z = -1.5\)[/tex]
- [tex]\(s = 3.6\)[/tex]

Substitute these values into the formula:

[tex]\[ x = 29 + (-1.5) \cdot 3.6 \][/tex]

Calculate the product of [tex]\(z\)[/tex] and [tex]\(s\)[/tex]:

[tex]\[ -1.5 \cdot 3.6 = -5.4 \][/tex]

Now add this result to the mean:

[tex]\[ x = 29 - 5.4 \][/tex]

[tex]\[ x = 23.6 \][/tex]

Therefore, the mileage that corresponds to a [tex]$z$[/tex]-score of -1.5 is 23.6 miles. Among the given options, the closest mileage is:

24 miles
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