To determine the phenotype ratio for this cross, let's analyze the given Punnett square:
[tex]\[
\begin{tabular}{|c|c|c|}
\hline & $t$ & $t$ \\
\hline $T$ & $Tt$ & $Tt$ \\
\hline $t$ & $tt$ & $tt$ \\
\hline
\end{tabular}
\][/tex]
From the Punnett square, we can observe the resulting genotypes for the offspring of these two parents:
1. [tex]\(Tt\)[/tex]
2. [tex]\(Tt\)[/tex]
3. [tex]\(tt\)[/tex]
4. [tex]\(tt\)[/tex]
Next, let's count the occurrences of each genotype:
- [tex]\(Tt\)[/tex]: 2 times
- [tex]\(tt\)[/tex]: 2 times
Now, we need to translate these genotypes into the corresponding phenotypes.
- Genotype [tex]\(Tt\)[/tex] (heterozygous) results in a short tail, as the trait for short tails is dominant.
- Genotype [tex]\(tt\)[/tex] (homozygous recessive) results in a long tail, as the trait for long tails is recessive.
From the counts we determined:
- 2 offspring have the genotype [tex]\(Tt\)[/tex], which corresponds to the short tail phenotype.
- 2 offspring have the genotype [tex]\(tt\)[/tex], which corresponds to the long tail phenotype.
Thus, the phenotype ratio is:
- 2 short tails
- 2 long tails
The correct answer is:
A. 2 long, 2 short
