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```latex
\begin{array}{c}
x + 6y = 5 \\
3x - 7y = -35 \\
\text{Solution: } (-7, 2)
\end{array}

\begin{aligned}
x + 6y &= 5 \\
-2y &= -50
\end{aligned}

The solution to System B will be the same as the solution to System A.
```

Sagot :

GinnyAnswer
Sure, let's solve the given system B step-by-step:

[tex]\[ \begin{aligned} 1) & \quad x + 6y = 5 \\ 2) & \quad -2y = -50 \end{aligned} \][/tex]

First, isolate [tex]\( y \)[/tex] in the second equation:

[tex]\[ -2y = -50 \][/tex]

Divide both sides by -2:

[tex]\[ y = \frac{-50}{-2} \Rightarrow y = 25 \][/tex]

Now that we have [tex]\( y = 25 \)[/tex], substitute this value into the first equation [tex]\( x + 6y = 5 \)[/tex]:

[tex]\[ x + 6(25) = 5 \][/tex]

Simplify inside the parenthesis:

[tex]\[ x + 150 = 5 \][/tex]

Next, isolate [tex]\( x \)[/tex] by subtracting 150 from both sides of the equation:

[tex]\[ x + 150 - 150 = 5 - 150 \Rightarrow x = -145 \][/tex]

So, the solution to the system B is:

[tex]\[ x = -145 \quad \text{and} \quad y = 25 \][/tex]

Thus, the solution is [tex]\((-145, 25)\)[/tex].
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