Discover the answers to your questions at Westonci.ca, where experts share their knowledge and insights with you. Discover comprehensive solutions to your questions from a wide network of experts on our user-friendly platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.
Sagot :
To determine which numbers are irrational, we need to analyze each of the given numbers:
1. Number: [tex]\( -2.3456 \)[/tex]
- This number has a finite decimal representation.
- Numbers with finite decimal representations are rational.
- Therefore, [tex]\( -2.3456 \)[/tex] is not irrational.
2. Number: [tex]\( \frac{\pi}{4} \)[/tex]
- The number [tex]\(\pi\)[/tex] is well-known to be irrational.
- When you divide an irrational number by a rational, the result remains irrational.
- Therefore, [tex]\( \frac{\pi}{4} \)[/tex] is irrational.
3. Number: [tex]\( \sqrt[3]{9} \)[/tex] (the cube root of 9)
- To determine if [tex]\( \sqrt[3]{9} \)[/tex] is rational or irrational, consider this:
- [tex]\( \sqrt[3]{9} \)[/tex] is not an integer or a fraction that can be expressed in the form [tex]\( \frac{a}{b} \)[/tex] where a and b are integers and b is not zero.
- Therefore, [tex]\( \sqrt[3]{9} \)[/tex] is an irrational number.
4. Number: [tex]\( 2 + \sqrt{16} \)[/tex]
- Calculate [tex]\( \sqrt{16} \)[/tex], which equals 4.
- Thus, [tex]\( 2 + \sqrt{16} = 2 + 4 = 6 \)[/tex].
- The number 6 is a rational number because it can be written as [tex]\( \frac{6}{1} \)[/tex].
- Therefore, [tex]\( 2 + \sqrt{16} \)[/tex] is not irrational.
With this analysis in mind, we summarize which numbers are irrational:
- List of Irrational Numbers: [tex]\( \frac{\pi}{4} \)[/tex] and [tex]\( \sqrt[3]{9} \)[/tex].
Now, we match these findings with the given options:
- Option 1: [tex]\(-2.3456\)[/tex] and [tex]\(2 + \sqrt{16}\)[/tex]
- Both numbers are rational, so this is not the correct choice.
- Option 2: [tex]\(-2.3456\)[/tex] and [tex]\(\frac{\pi}{4}\)[/tex]
- Only one of the numbers is irrational, so this is not the correct choice.
- Option 3: [tex]\(\sqrt[3]{9}\)[/tex] and [tex]\(2 + \sqrt{16}\)[/tex]
- Only one of the numbers is irrational, so this is not the correct choice.
- Option 4: [tex]\(\frac{\pi}{4}\)[/tex] and [tex]\(\sqrt[3]{9}\)[/tex]
- Both numbers are irrational, so this is the correct choice.
Therefore, the correct answer is:
[tex]\[ \boxed{\frac{\pi}{4} \text{ and } \sqrt[3]{9}} \][/tex]
1. Number: [tex]\( -2.3456 \)[/tex]
- This number has a finite decimal representation.
- Numbers with finite decimal representations are rational.
- Therefore, [tex]\( -2.3456 \)[/tex] is not irrational.
2. Number: [tex]\( \frac{\pi}{4} \)[/tex]
- The number [tex]\(\pi\)[/tex] is well-known to be irrational.
- When you divide an irrational number by a rational, the result remains irrational.
- Therefore, [tex]\( \frac{\pi}{4} \)[/tex] is irrational.
3. Number: [tex]\( \sqrt[3]{9} \)[/tex] (the cube root of 9)
- To determine if [tex]\( \sqrt[3]{9} \)[/tex] is rational or irrational, consider this:
- [tex]\( \sqrt[3]{9} \)[/tex] is not an integer or a fraction that can be expressed in the form [tex]\( \frac{a}{b} \)[/tex] where a and b are integers and b is not zero.
- Therefore, [tex]\( \sqrt[3]{9} \)[/tex] is an irrational number.
4. Number: [tex]\( 2 + \sqrt{16} \)[/tex]
- Calculate [tex]\( \sqrt{16} \)[/tex], which equals 4.
- Thus, [tex]\( 2 + \sqrt{16} = 2 + 4 = 6 \)[/tex].
- The number 6 is a rational number because it can be written as [tex]\( \frac{6}{1} \)[/tex].
- Therefore, [tex]\( 2 + \sqrt{16} \)[/tex] is not irrational.
With this analysis in mind, we summarize which numbers are irrational:
- List of Irrational Numbers: [tex]\( \frac{\pi}{4} \)[/tex] and [tex]\( \sqrt[3]{9} \)[/tex].
Now, we match these findings with the given options:
- Option 1: [tex]\(-2.3456\)[/tex] and [tex]\(2 + \sqrt{16}\)[/tex]
- Both numbers are rational, so this is not the correct choice.
- Option 2: [tex]\(-2.3456\)[/tex] and [tex]\(\frac{\pi}{4}\)[/tex]
- Only one of the numbers is irrational, so this is not the correct choice.
- Option 3: [tex]\(\sqrt[3]{9}\)[/tex] and [tex]\(2 + \sqrt{16}\)[/tex]
- Only one of the numbers is irrational, so this is not the correct choice.
- Option 4: [tex]\(\frac{\pi}{4}\)[/tex] and [tex]\(\sqrt[3]{9}\)[/tex]
- Both numbers are irrational, so this is the correct choice.
Therefore, the correct answer is:
[tex]\[ \boxed{\frac{\pi}{4} \text{ and } \sqrt[3]{9}} \][/tex]
Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.