Westonci.ca is the best place to get answers to your questions, provided by a community of experienced and knowledgeable experts. Discover comprehensive solutions to your questions from a wide network of experts on our user-friendly platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
Sure, let's find the first three terms of the arithmetic series given the first term [tex]\( a_1 = 3 \)[/tex], the [tex]\( n \)[/tex]-th term [tex]\( a_n = 24 \)[/tex], and the sum of the first [tex]\( n \)[/tex] terms [tex]\( S_n = 108 \)[/tex].
We'll approach this problem step-by-step:
### Step 1: Find the number of terms [tex]\( n \)[/tex]
The sum of the first [tex]\( n \)[/tex] terms of an arithmetic series is given by the formula:
[tex]\[ S_n = \frac{n}{2} (a_1 + a_n) \][/tex]
Given:
[tex]\[ S_n = 108 \][/tex]
[tex]\[ a_1 = 3 \][/tex]
[tex]\[ a_n = 24 \][/tex]
We can substitute these values into the formula to solve for [tex]\( n \)[/tex]:
[tex]\[ 108 = \frac{n}{2} (3 + 24) \][/tex]
Simplify inside the parentheses:
[tex]\[ 108 = \frac{n}{2} \times 27 \][/tex]
To clear the fraction, multiply both sides by 2:
[tex]\[ 216 = 27n \][/tex]
Solve for [tex]\( n \)[/tex]:
[tex]\[ n = \frac{216}{27} \][/tex]
[tex]\[ n = 8 \][/tex]
So, there are 8 terms in the arithmetic series.
### Step 2: Find the common difference [tex]\( d \)[/tex]
The [tex]\( n \)[/tex]-th term of an arithmetic series is given by the formula:
[tex]\[ a_n = a_1 + (n - 1)d \][/tex]
Given:
[tex]\[ a_n = 24 \][/tex]
[tex]\[ a_1 = 3 \][/tex]
[tex]\[ n = 8 \][/tex]
We can substitute these values into the formula to solve for [tex]\( d \)[/tex]:
[tex]\[ 24 = 3 + (8 - 1)d \][/tex]
Simplify the equation:
[tex]\[ 24 = 3 + 7d \][/tex]
Subtract 3 from both sides:
[tex]\[ 21 = 7d \][/tex]
Solve for [tex]\( d \)[/tex]:
[tex]\[ d = \frac{21}{7} \][/tex]
[tex]\[ d = 3 \][/tex]
So, the common difference [tex]\( d \)[/tex] is 3.
### Step 3: Find the first three terms
The first term [tex]\( a_1 \)[/tex] is already given as 3.
To find the second term [tex]\( a_2 \)[/tex]:
[tex]\[ a_2 = a_1 + d \][/tex]
[tex]\[ a_2 = 3 + 3 \][/tex]
[tex]\[ a_2 = 6 \][/tex]
To find the third term [tex]\( a_3 \)[/tex]:
[tex]\[ a_3 = a_1 + 2d \][/tex]
[tex]\[ a_3 = 3 + 2 \times 3 \][/tex]
[tex]\[ a_3 = 3 + 6 \][/tex]
[tex]\[ a_3 = 9 \][/tex]
### Conclusion
The first three terms of the arithmetic series are:
1. [tex]\( a_1 = 3 \)[/tex]
2. [tex]\( a_2 = 6 \)[/tex]
3. [tex]\( a_3 = 9 \)[/tex]
We'll approach this problem step-by-step:
### Step 1: Find the number of terms [tex]\( n \)[/tex]
The sum of the first [tex]\( n \)[/tex] terms of an arithmetic series is given by the formula:
[tex]\[ S_n = \frac{n}{2} (a_1 + a_n) \][/tex]
Given:
[tex]\[ S_n = 108 \][/tex]
[tex]\[ a_1 = 3 \][/tex]
[tex]\[ a_n = 24 \][/tex]
We can substitute these values into the formula to solve for [tex]\( n \)[/tex]:
[tex]\[ 108 = \frac{n}{2} (3 + 24) \][/tex]
Simplify inside the parentheses:
[tex]\[ 108 = \frac{n}{2} \times 27 \][/tex]
To clear the fraction, multiply both sides by 2:
[tex]\[ 216 = 27n \][/tex]
Solve for [tex]\( n \)[/tex]:
[tex]\[ n = \frac{216}{27} \][/tex]
[tex]\[ n = 8 \][/tex]
So, there are 8 terms in the arithmetic series.
### Step 2: Find the common difference [tex]\( d \)[/tex]
The [tex]\( n \)[/tex]-th term of an arithmetic series is given by the formula:
[tex]\[ a_n = a_1 + (n - 1)d \][/tex]
Given:
[tex]\[ a_n = 24 \][/tex]
[tex]\[ a_1 = 3 \][/tex]
[tex]\[ n = 8 \][/tex]
We can substitute these values into the formula to solve for [tex]\( d \)[/tex]:
[tex]\[ 24 = 3 + (8 - 1)d \][/tex]
Simplify the equation:
[tex]\[ 24 = 3 + 7d \][/tex]
Subtract 3 from both sides:
[tex]\[ 21 = 7d \][/tex]
Solve for [tex]\( d \)[/tex]:
[tex]\[ d = \frac{21}{7} \][/tex]
[tex]\[ d = 3 \][/tex]
So, the common difference [tex]\( d \)[/tex] is 3.
### Step 3: Find the first three terms
The first term [tex]\( a_1 \)[/tex] is already given as 3.
To find the second term [tex]\( a_2 \)[/tex]:
[tex]\[ a_2 = a_1 + d \][/tex]
[tex]\[ a_2 = 3 + 3 \][/tex]
[tex]\[ a_2 = 6 \][/tex]
To find the third term [tex]\( a_3 \)[/tex]:
[tex]\[ a_3 = a_1 + 2d \][/tex]
[tex]\[ a_3 = 3 + 2 \times 3 \][/tex]
[tex]\[ a_3 = 3 + 6 \][/tex]
[tex]\[ a_3 = 9 \][/tex]
### Conclusion
The first three terms of the arithmetic series are:
1. [tex]\( a_1 = 3 \)[/tex]
2. [tex]\( a_2 = 6 \)[/tex]
3. [tex]\( a_3 = 9 \)[/tex]
We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.