Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Get the answers you need quickly and accurately from a dedicated community of experts on our Q&A platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

Given the functions:

[tex]\[ h(x) = x^2 + 1 \][/tex]
[tex]\[ k(x) = x - 2 \][/tex]

Evaluate [tex]\((h + k)(2)\)[/tex].


Sagot :

To solve for [tex]\((h+k)(2)\)[/tex], follow these steps:

1. Calculate [tex]\(h(x)\)[/tex] at [tex]\(x = 2\)[/tex]:
- Given [tex]\(h(x) = x^2 + 1\)[/tex], substitute [tex]\(x = 2\)[/tex]:
[tex]\[ h(2) = 2^2 + 1 = 4 + 1 = 5 \][/tex]

2. Calculate [tex]\(k(x)\)[/tex] at [tex]\(x = 2\)[/tex]:
- Given [tex]\(k(x) = x - 2\)[/tex], substitute [tex]\(x = 2\)[/tex]:
[tex]\[ k(2) = 2 - 2 = 0 \][/tex]

3. Combine [tex]\(h(2)\)[/tex] and [tex]\(k(2)\)[/tex] to find [tex]\((h + k)(2)\)[/tex]:
- [tex]\((h + k)(2)\)[/tex] means adding the values of [tex]\(h(2)\)[/tex] and [tex]\(k(2)\)[/tex]:
[tex]\[ (h + k)(2) = h(2) + k(2) = 5 + 0 = 5 \][/tex]

Therefore, the value of [tex]\((h+k)(2)\)[/tex] is:
[tex]\[ (h+k)(2) = 5 \][/tex]
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.