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Given the function [tex]F(x) = 4x^2 + 2[/tex], answer the following questions:

1. What is the value of [tex]F(2)[/tex]?
2. What is the vertex of the function?
3. What is the axis of symmetry?
4. Is the parabola opening upwards or downwards?

Sagot :

Given the function [tex]\( F(x) = 4x^2 + 2 \)[/tex], let's break down and understand the components and steps involved in evaluating or analyzing this quadratic function.

1. Identify the Function:
The function is a quadratic expression in the form:
[tex]\[ F(x) = 4x^2 + 2 \][/tex]

2. Standard Form of a Quadratic Function:
A quadratic function is generally expressed in the standard form:
[tex]\[ ax^2 + bx + c \][/tex]
Here, [tex]\( a = 4 \)[/tex], [tex]\( b = 0 \)[/tex], and [tex]\( c = 2 \)[/tex]. This identifies the coefficients and constants associated with the quadratic function.

3. Vertex of the Quadratic Function:
The vertex form of a quadratic function is:
[tex]\[ F(x) = a(x-h)^2 + k \][/tex]
where [tex]\((h, k)\)[/tex] is the vertex of the parabola. For our function [tex]\( F(x) = 4x^2 + 2 \)[/tex]:
- Since there is no [tex]\( x \)[/tex] term (i.e., [tex]\( b = 0 \)[/tex]), the vertex is at [tex]\( x = 0 \)[/tex].
- Plugging [tex]\( x = 0 \)[/tex] into the function, we get the vertex:
[tex]\[ F(0) = 4(0)^2 + 2 = 2 \][/tex]
Thus, the vertex is [tex]\((0, 2)\)[/tex].

4. Y-Intercept:
The y-intercept occurs when [tex]\( x = 0 \)[/tex]. Evaluating the function at [tex]\( x = 0 \)[/tex]:
[tex]\[ F(0) = 2 \][/tex]
So, the y-intercept is [tex]\( (0, 2) \)[/tex].

5. Axis of Symmetry:
The axis of symmetry for a quadratic function [tex]\( ax^2 + bx + c \)[/tex] is given by:
[tex]\[ x = -\frac{b}{2a} \][/tex]
Since [tex]\( b = 0 \)[/tex], the axis of symmetry is:
[tex]\[ x = -\frac{0}{2(4)} = 0 \][/tex]

6. Direction of the Parabola:
Since the coefficient [tex]\( a = 4 \)[/tex] is positive, the parabola opens upwards.

7. General Shape and Behavior:
- The parabola opens upward.
- The vertex at [tex]\( (0, 2) \)[/tex] is the minimum point of the function.
- The y-intercept is at [tex]\( (0, 2) \)[/tex].

8. Graphical Representation:
- Plot the vertex at [tex]\( (0, 2) \)[/tex].
- Draw the axis of symmetry along [tex]\( x = 0 \)[/tex].
- Sketch the parabola opening upward from the vertex.

By following these steps, you can fully understand and visualize the quadratic function [tex]\( F(x) = 4x^2 + 2 \)[/tex].