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The formula [tex]$S = 0.6T + 331.5$[/tex] gives the approximate speed of sound in air, [tex]$S$[/tex] meters per second, when the temperature is [tex][tex]$T$[/tex][/tex] degrees Celsius.

Determine the speed of sound at [tex]$40^{\circ} C$[/tex].

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GinnyAnswer
To determine the speed of sound at a temperature of [tex]\( 40^\circ \text{C} \)[/tex], we use the given formula:

[tex]\[ S = 0.6T + 331.5 \][/tex]

Here, [tex]\( S \)[/tex] represents the speed of sound in meters per second, and [tex]\( T \)[/tex] represents the temperature in degrees Celsius.

We are given [tex]\( T = 40 \)[/tex] degrees Celsius. Now, we substitute this value into the formula:

[tex]\[ S = 0.6 \times 40 + 331.5 \][/tex]

First, we calculate the product of [tex]\( 0.6 \)[/tex] and [tex]\( 40 \)[/tex]:

[tex]\[ 0.6 \times 40 = 24 \][/tex]

Next, we add this result to [tex]\( 331.5 \)[/tex]:

[tex]\[ 24 + 331.5 = 355.5 \][/tex]

Therefore, the speed of sound at [tex]\( 40^\circ \text{C} \)[/tex] is:

[tex]\[ S = 355.5 \, \text{meters per second} \][/tex]
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