Answered

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The force of attraction between two oppositely charged pith balls is 5.3* 10⁻⁶ newtons. If the charge on the two objects is 6.7* 10⁻⁹ coulombs, what is the distance between the two charges? (k=9.0* 10⁻⁹ newton-meter²/co Jlombs²)
A. 2.76* 10⁻¹ meters
B. 7.0* 10⁻¹ meters
C. 6.7* 10⁻¹ meters
D. 8.2* 10⁻¹ meters
E. 9.6* 10⁻¹ meters

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