An object thrown vertically upward from the surface of a celestial body at a velocity of 42 m/s reaches a height of s=−0.6t²+42t meters in t seconds.
Determine the velocity v of the object after t seconds.

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04-07-2024
Mathematics

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An object thrown vertically upward from the surface of a celestial body at a velocity of 42 m/s reaches a height of s=−0.6t²+42t meters in t seconds.
Determine the velocity v of the object after t seconds.

Sagot :

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An object thrown vertically upward from the surface of a celestial body at a velocity of 42 m/s reaches a height of s=−0.6t²+42t meters in t seconds. Determine the velocity v of the object after t seconds.

Sagot :

Other Questions

An object thrown vertically upward from the surface of a celestial body at a velocity of 42 m/s reaches a height of s=−0.6t²+42t meters in t seconds.
Determine the velocity v of the object after t seconds.