Explore Westonci.ca, the leading Q&A site where experts provide accurate and helpful answers to all your questions. Join our Q&A platform to connect with experts dedicated to providing precise answers to your questions in different areas. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
To simplify and solve the expression [tex]\(\sqrt{\frac{1 + \cos A}{1 - \cos A}}\)[/tex], we will use trigonometric identities and step-by-step manipulation. Here’s a comprehensive breakdown:
### Step 1: Recall Trigonometric Identities
To simplify the given expression, let's use the following trigonometric identities:
1. [tex]\(\cos A = 1 - 2\sin^2\left(\frac{A}{2}\right)\)[/tex]
2. [tex]\(1 - \cos A = 2\sin^2\left(\frac{A}{2}\right)\)[/tex]
3. [tex]\(1 + \cos A = 2\cos^2\left(\frac{A}{2}\right)\)[/tex]
### Step 2: Apply the Identities
Rewrite the components of the fraction using the identities:
[tex]\[ 1 + \cos A = 2\cos^2\left(\frac{A}{2}\right) \][/tex]
[tex]\[ 1 - \cos A = 2\sin^2\left(\frac{A}{2}\right) \][/tex]
### Step 3: Substitute the Identities
Now, substitute these into our original expression:
[tex]\[ \sqrt{\frac{1 + \cos A}{1 - \cos A}} = \sqrt{\frac{2\cos^2\left(\frac{A}{2}\right)}{2\sin^2\left(\frac{A}{2}\right)}} \][/tex]
### Step 4: Simplify the Fraction
Simplify the fraction inside the square root:
[tex]\[ \sqrt{\frac{2\cos^2\left(\frac{A}{2}\right)}{2\sin^2\left(\frac{A}{2}\right)}} = \sqrt{\frac{\cos^2\left(\frac{A}{2}\right)}{\sin^2\left(\frac{A}{2}\right)}} \][/tex]
### Step 5: Simplify the Expression Further
This can be further simplified because the fraction of squares can be reduced:
[tex]\[ \sqrt{\frac{\cos^2\left(\frac{A}{2}\right)}{\sin^2\left(\frac{A}{2}\right)}} = \sqrt{\left(\frac{\cos\left(\frac{A}{2}\right)}{\sin\left(\frac{A}{2}\right)}\right)^2} \][/tex]
### Step 6: Take the Square Root
Now, taking the square root of a square:
[tex]\[ \sqrt{\left(\frac{\cos\left(\frac{A}{2}\right)}{\sin\left(\frac{A}{2}\right)}\right)^2} = \left| \frac{\cos\left(\frac{A}{2}\right)}{\sin\left(\frac{A}{2}\right)} \right| \][/tex]
Since [tex]\(\frac{\cos\left(\frac{A}{2}\right)}{\sin\left(\frac{A}{2}\right)}\)[/tex] is the cotangent of [tex]\(\frac{A}{2}\)[/tex], we have:
[tex]\[ \left| \frac{\cos\left(\frac{A}{2}\right)}{\sin\left(\frac{A}{2}\right)} \right| = \left| \cot \left(\frac{A}{2}\right) \right| \][/tex]
### Final Answer
Thus, the expression simplifies to:
[tex]\[ \sqrt{\frac{1 + \cos A}{1 - \cos A}} = \left| \cot \left(\frac{A}{2}\right) \right| \][/tex]
The absolute value notation is due to the fact that square roots yield non-negative results, while the cotangent function can be either positive or negative depending on the angle.
### Step 1: Recall Trigonometric Identities
To simplify the given expression, let's use the following trigonometric identities:
1. [tex]\(\cos A = 1 - 2\sin^2\left(\frac{A}{2}\right)\)[/tex]
2. [tex]\(1 - \cos A = 2\sin^2\left(\frac{A}{2}\right)\)[/tex]
3. [tex]\(1 + \cos A = 2\cos^2\left(\frac{A}{2}\right)\)[/tex]
### Step 2: Apply the Identities
Rewrite the components of the fraction using the identities:
[tex]\[ 1 + \cos A = 2\cos^2\left(\frac{A}{2}\right) \][/tex]
[tex]\[ 1 - \cos A = 2\sin^2\left(\frac{A}{2}\right) \][/tex]
### Step 3: Substitute the Identities
Now, substitute these into our original expression:
[tex]\[ \sqrt{\frac{1 + \cos A}{1 - \cos A}} = \sqrt{\frac{2\cos^2\left(\frac{A}{2}\right)}{2\sin^2\left(\frac{A}{2}\right)}} \][/tex]
### Step 4: Simplify the Fraction
Simplify the fraction inside the square root:
[tex]\[ \sqrt{\frac{2\cos^2\left(\frac{A}{2}\right)}{2\sin^2\left(\frac{A}{2}\right)}} = \sqrt{\frac{\cos^2\left(\frac{A}{2}\right)}{\sin^2\left(\frac{A}{2}\right)}} \][/tex]
### Step 5: Simplify the Expression Further
This can be further simplified because the fraction of squares can be reduced:
[tex]\[ \sqrt{\frac{\cos^2\left(\frac{A}{2}\right)}{\sin^2\left(\frac{A}{2}\right)}} = \sqrt{\left(\frac{\cos\left(\frac{A}{2}\right)}{\sin\left(\frac{A}{2}\right)}\right)^2} \][/tex]
### Step 6: Take the Square Root
Now, taking the square root of a square:
[tex]\[ \sqrt{\left(\frac{\cos\left(\frac{A}{2}\right)}{\sin\left(\frac{A}{2}\right)}\right)^2} = \left| \frac{\cos\left(\frac{A}{2}\right)}{\sin\left(\frac{A}{2}\right)} \right| \][/tex]
Since [tex]\(\frac{\cos\left(\frac{A}{2}\right)}{\sin\left(\frac{A}{2}\right)}\)[/tex] is the cotangent of [tex]\(\frac{A}{2}\)[/tex], we have:
[tex]\[ \left| \frac{\cos\left(\frac{A}{2}\right)}{\sin\left(\frac{A}{2}\right)} \right| = \left| \cot \left(\frac{A}{2}\right) \right| \][/tex]
### Final Answer
Thus, the expression simplifies to:
[tex]\[ \sqrt{\frac{1 + \cos A}{1 - \cos A}} = \left| \cot \left(\frac{A}{2}\right) \right| \][/tex]
The absolute value notation is due to the fact that square roots yield non-negative results, while the cotangent function can be either positive or negative depending on the angle.
Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.