At Westonci.ca, we provide clear, reliable answers to all your questions. Join our vibrant community and get the solutions you need. Get the answers you need quickly and accurately from a dedicated community of experts on our Q&A platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
Let's address each part of the question step-by-step.
### Part (a): Write a Sinusoidal Function
To write a sinusoidal function that models Omaha's monthly temperature variation, we will use the general form of a sinusoidal function, which can be written as:
[tex]\[ T(t) = A \sin\left(\frac{2\pi}{P} (t - \phi)\right) + M \][/tex]
where:
- [tex]\( T(t) \)[/tex] is the temperature at month [tex]\( t \)[/tex].
- [tex]\( A \)[/tex] is the amplitude, which represents half the range of temperature variations.
- [tex]\( P \)[/tex] is the period, which for a yearly cycle is 12 months.
- [tex]\( \phi \)[/tex] is the phase shift, which shifts the curve horizontally to align with the temperature data.
- [tex]\( M \)[/tex] is the midline, which is the average temperature over the year.
#### Step 1: Calculate the Midline ([tex]\( M \)[/tex])
The midline [tex]\( M \)[/tex] can be calculated as the average of the maximum and minimum temperatures.
Given the temperatures: [21, 27, 39, 52, 62, 72, 77, 74, 65, 53, 39, 25],
- Maximum temperature = [tex]\( 77^{\circ}F \)[/tex]
- Minimum temperature = [tex]\( 21^{\circ}F \)[/tex]
The midline [tex]\( M \)[/tex] is given by:
[tex]\[ M = \frac{\text{Max Temp} + \text{Min Temp}}{2} = \frac{77 + 21}{2} = 49^{\circ}F \][/tex]
#### Step 2: Calculate the Amplitude ([tex]\( A \)[/tex])
The amplitude [tex]\( A \)[/tex] is half the difference between the maximum and minimum temperatures.
[tex]\[ A = \frac{\text{Max Temp} - \text{Min Temp}}{2} = \frac{77 - 21}{2} = 28^{\circ}F \][/tex]
#### Step 3: Determine the Period ([tex]\( P \)[/tex])
The period [tex]\( P \)[/tex] for our scenario is the length of one full cycle and, since the data is for a yearly cycle, [tex]\( P = 12 \)[/tex] months.
#### Step 4: Calculate the Phase Shift ([tex]\( \phi \)[/tex])
To find the phase shift, we locate the month with the peak temperature.
The highest temperature [tex]\( 77^{\circ}F \)[/tex] occurs in July (month 7). For a standard sine function, the peak would occur at [tex]\( t = \frac{P}{4} \)[/tex] (3 months).
Therefore, the phase shift [tex]\( \phi \)[/tex] aligns this with month 7:
[tex]\[ \phi = 7 - 3 = 4 \][/tex]
#### Final Sinusoidal Function
With all these values, the sinusoidal function that models Omaha’s monthly temperature variation is:
[tex]\[ T(t) = 28 \sin\left(\frac{2\pi}{12} (t - 4)\right) + 49 \][/tex]
### Part (b): Estimate the Normal Temperature in April
To estimate the normal temperature for the month of April using the sinusoidal model, we substitute [tex]\( t = 4 \)[/tex] into our function.
[tex]\[ T(4) = 28 \sin\left(\frac{2\pi}{12} (4 - 4)\right) + 49 \][/tex]
Simplifying inside the sine function:
[tex]\[ T(4) = 28 \sin(0) + 49 \][/tex]
Since [tex]\( \sin(0) = 0 \)[/tex]:
[tex]\[ T(4) = 28 \cdot 0 + 49 = 49 \][/tex]
Therefore, the estimated normal temperature during the month of April is [tex]\( 49^{\circ}F \)[/tex].
### Part (a): Write a Sinusoidal Function
To write a sinusoidal function that models Omaha's monthly temperature variation, we will use the general form of a sinusoidal function, which can be written as:
[tex]\[ T(t) = A \sin\left(\frac{2\pi}{P} (t - \phi)\right) + M \][/tex]
where:
- [tex]\( T(t) \)[/tex] is the temperature at month [tex]\( t \)[/tex].
- [tex]\( A \)[/tex] is the amplitude, which represents half the range of temperature variations.
- [tex]\( P \)[/tex] is the period, which for a yearly cycle is 12 months.
- [tex]\( \phi \)[/tex] is the phase shift, which shifts the curve horizontally to align with the temperature data.
- [tex]\( M \)[/tex] is the midline, which is the average temperature over the year.
#### Step 1: Calculate the Midline ([tex]\( M \)[/tex])
The midline [tex]\( M \)[/tex] can be calculated as the average of the maximum and minimum temperatures.
Given the temperatures: [21, 27, 39, 52, 62, 72, 77, 74, 65, 53, 39, 25],
- Maximum temperature = [tex]\( 77^{\circ}F \)[/tex]
- Minimum temperature = [tex]\( 21^{\circ}F \)[/tex]
The midline [tex]\( M \)[/tex] is given by:
[tex]\[ M = \frac{\text{Max Temp} + \text{Min Temp}}{2} = \frac{77 + 21}{2} = 49^{\circ}F \][/tex]
#### Step 2: Calculate the Amplitude ([tex]\( A \)[/tex])
The amplitude [tex]\( A \)[/tex] is half the difference between the maximum and minimum temperatures.
[tex]\[ A = \frac{\text{Max Temp} - \text{Min Temp}}{2} = \frac{77 - 21}{2} = 28^{\circ}F \][/tex]
#### Step 3: Determine the Period ([tex]\( P \)[/tex])
The period [tex]\( P \)[/tex] for our scenario is the length of one full cycle and, since the data is for a yearly cycle, [tex]\( P = 12 \)[/tex] months.
#### Step 4: Calculate the Phase Shift ([tex]\( \phi \)[/tex])
To find the phase shift, we locate the month with the peak temperature.
The highest temperature [tex]\( 77^{\circ}F \)[/tex] occurs in July (month 7). For a standard sine function, the peak would occur at [tex]\( t = \frac{P}{4} \)[/tex] (3 months).
Therefore, the phase shift [tex]\( \phi \)[/tex] aligns this with month 7:
[tex]\[ \phi = 7 - 3 = 4 \][/tex]
#### Final Sinusoidal Function
With all these values, the sinusoidal function that models Omaha’s monthly temperature variation is:
[tex]\[ T(t) = 28 \sin\left(\frac{2\pi}{12} (t - 4)\right) + 49 \][/tex]
### Part (b): Estimate the Normal Temperature in April
To estimate the normal temperature for the month of April using the sinusoidal model, we substitute [tex]\( t = 4 \)[/tex] into our function.
[tex]\[ T(4) = 28 \sin\left(\frac{2\pi}{12} (4 - 4)\right) + 49 \][/tex]
Simplifying inside the sine function:
[tex]\[ T(4) = 28 \sin(0) + 49 \][/tex]
Since [tex]\( \sin(0) = 0 \)[/tex]:
[tex]\[ T(4) = 28 \cdot 0 + 49 = 49 \][/tex]
Therefore, the estimated normal temperature during the month of April is [tex]\( 49^{\circ}F \)[/tex].
Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.