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Let's find the antiderivative of [tex]$\int 7 x^6 (x^7+9)^3 \, dx$[/tex] using substitution. Let [tex]$u = x^7 + 9$[/tex].

First, let's find [tex]du[/tex] by taking the derivative of [tex]u[/tex]:
[tex]du = 7x^6 \, dx[/tex]

Note: Don't forget to include [tex]dx[/tex] in your answer.

Part 2 of 4

Now, let's rewrite our antiderivative in terms of [tex]u[/tex]:
[tex]\int 7 x^6 (x^7+9)^3 \, dx = \int u^3 \, du[/tex]


Sagot :

Certainly! Let's go through the steps to find the antiderivative of [tex]\(\int 7 x^6 (x^7 + 9)^3 \, dx\)[/tex] using substitution. Given the substitution [tex]\(u = x^7 + 9\)[/tex], we proceed as follows.

1. Substitution and Differentiation:
First, let's find the differential [tex]\(du\)[/tex] by taking the derivative of [tex]\(u\)[/tex] with respect to [tex]\(x\)[/tex].

Since [tex]\(u = x^7 + 9\)[/tex],

[tex]\[ \frac{du}{dx} = \frac{d}{dx}(x^7 + 9) = 7x^6. \][/tex]

Therefore,

[tex]\[ du = 7x^6 \, dx. \][/tex]

This implies,

[tex]\[ dx = \frac{du}{7x^6}. \][/tex]

2. Rewrite the Integral in Terms of [tex]\(u\)[/tex]:
Now, substitute [tex]\(u = x^7 + 9\)[/tex] into the integral. Also, use the relationship [tex]\(dx = \frac{du}{7x^6}\)[/tex].

The integrand [tex]\(7 x^6 (x^7 + 9)^3\)[/tex] can be rewritten as:

[tex]\[ 7 x^6 u^3. \][/tex]

Incorporating the expression for [tex]\(dx\)[/tex], we get:

[tex]\[ \int 7 x^6 u^3 \cdot \frac{du}{7x^6}. \][/tex]

3. Simplify:
The [tex]\(7 x^6\)[/tex] terms cancel out, leaving:

[tex]\[ \int u^3 \, du. \][/tex]

4. Find the Antiderivative:
Now, integrate with respect to [tex]\(u\)[/tex]:

[tex]\[ \int u^3 \, du = \frac{u^4}{4} + C. \][/tex]

Finally, substitute back [tex]\(u = x^7 + 9\)[/tex] to express the answer in terms of [tex]\(x\)[/tex]:

[tex]\[ \frac{(x^7 + 9)^4}{4} + C. \][/tex]

Therefore, the antiderivative of the given integral is:

[tex]\[ \boxed{\frac{(x^7 + 9)^4}{4} + C}. \][/tex]

This captures the step-by-step solution for finding the antiderivative using the substitution method.
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