Welcome to Westonci.ca, where your questions are met with accurate answers from a community of experts and enthusiasts. Discover reliable solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
Let's solve this step-by-step:
We start with the given equation:
[tex]\[ 148 = 2(6w + 6h + hw) \][/tex]
First, distribute the 2 on the right-hand side:
[tex]\[ 148 = 12w + 12h + 2hw \][/tex]
We want to solve for [tex]\( w \)[/tex] in terms of [tex]\( h \)[/tex]. To do this, let's isolate [tex]\( w \)[/tex]:
1. Combine like terms on the right-hand side:
[tex]\[ 148 = 12w + 12h + 2hw \][/tex]
2. Move the [tex]\( 12h \)[/tex] term to the left-hand side:
[tex]\[ 148 - 12h = 12w + 2hw \][/tex]
3. Factor [tex]\( w \)[/tex] out of the terms on the right-hand side:
[tex]\[ 148 - 12h = w(12 + 2h) \][/tex]
4. Divide both sides by [tex]\( (12 + 2h) \)[/tex] to isolate [tex]\( w \)[/tex]:
[tex]\[ w = \frac{148 - 12h}{12 + 2h} \][/tex]
Let's compare this to the given equivalent equations:
- [tex]\( w = \frac{148 - 6h}{12 + h} \)[/tex]
- [tex]\( w = \frac{148 - 12h}{12 + 2h} \)[/tex]
- [tex]\( w = 136 - 14h \)[/tex]
- [tex]\( w = 136 - 10h \)[/tex]
Comparing directly, we see that:
[tex]\[ w = \frac{148 - 12h}{12 + 2h} \][/tex]
is exactly equivalent to our derived equation because both the numerator and denominator match.
Thus, the equivalent equation is:
[tex]\[ w = \frac{148 - 12h}{12 + 2h} \][/tex]
So, the correct equation is:
[tex]\[ w = \frac{148 - 12h}{12 + 2h} \][/tex]
Therefore, the correct answer is the second option:
[tex]\[ w = \frac{148 - 12h}{12 + 2h} \][/tex]
We start with the given equation:
[tex]\[ 148 = 2(6w + 6h + hw) \][/tex]
First, distribute the 2 on the right-hand side:
[tex]\[ 148 = 12w + 12h + 2hw \][/tex]
We want to solve for [tex]\( w \)[/tex] in terms of [tex]\( h \)[/tex]. To do this, let's isolate [tex]\( w \)[/tex]:
1. Combine like terms on the right-hand side:
[tex]\[ 148 = 12w + 12h + 2hw \][/tex]
2. Move the [tex]\( 12h \)[/tex] term to the left-hand side:
[tex]\[ 148 - 12h = 12w + 2hw \][/tex]
3. Factor [tex]\( w \)[/tex] out of the terms on the right-hand side:
[tex]\[ 148 - 12h = w(12 + 2h) \][/tex]
4. Divide both sides by [tex]\( (12 + 2h) \)[/tex] to isolate [tex]\( w \)[/tex]:
[tex]\[ w = \frac{148 - 12h}{12 + 2h} \][/tex]
Let's compare this to the given equivalent equations:
- [tex]\( w = \frac{148 - 6h}{12 + h} \)[/tex]
- [tex]\( w = \frac{148 - 12h}{12 + 2h} \)[/tex]
- [tex]\( w = 136 - 14h \)[/tex]
- [tex]\( w = 136 - 10h \)[/tex]
Comparing directly, we see that:
[tex]\[ w = \frac{148 - 12h}{12 + 2h} \][/tex]
is exactly equivalent to our derived equation because both the numerator and denominator match.
Thus, the equivalent equation is:
[tex]\[ w = \frac{148 - 12h}{12 + 2h} \][/tex]
So, the correct equation is:
[tex]\[ w = \frac{148 - 12h}{12 + 2h} \][/tex]
Therefore, the correct answer is the second option:
[tex]\[ w = \frac{148 - 12h}{12 + 2h} \][/tex]
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.