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Two walls of a canyon form the walls of a steady flowing river. From a point on the shorter wall, the angle of elevation to the top of the opposing wall is 20° and the angle of depression to the bottom of the opposing wall is 45°. The distance from the top of the shorter wall to the bottom of the opposing wall is 290 feet. Using the appropriate right triangle solving strategies, solve for the following: (Do not round intermediate calculated values. Only the final answer should be rounded to one decimal place.)

Two Walls Of A Canyon Form The Walls Of A Steady Flowing River From A Point On The Shorter Wall The Angle Of Elevation To The Top Of The Opposing Wall Is 20 And class=

Sagot :

Answer:

Set your calculator to degree mode.

x = 290/√2 = 145√2

= about 205.1 feet

tan(20°) = a/290

a = 290tan(20°)

y = 145√2 + 290tan(20°)

= about 310.6 feet

z = 145√2 = about 205.1 feet

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