Answered

Explore Westonci.ca, the top Q&A platform where your questions are answered by professionals and enthusiasts alike. Our Q&A platform provides quick and trustworthy answers to your questions from experienced professionals in different areas of expertise. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

If you place a [tex]\(+0.638 \, \text{C}\)[/tex] charge at a point where the electric field is [tex]\(27.4 \, \text{N/C}\)[/tex] to the right, what electric force will it feel?

Include a + or - sign to indicate the direction of the force.
(Unit = N)

Sagot :

GinnyAnswer
To determine the electric force [tex]\( F \)[/tex] felt by a charge [tex]\( q \)[/tex] placed in an electric field [tex]\( E \)[/tex], we can use the formula:

[tex]\[ F = qE \][/tex]

Given:
- The charge [tex]\( q \)[/tex] is [tex]\( +0.638 \, \text{C} \)[/tex]
- The electric field [tex]\( E \)[/tex] is [tex]\( 27.4 \, \text{N/C} \)[/tex] to the right

Substitute the values into the formula:

[tex]\[ F = (+0.638 \, \text{C}) \times (27.4 \, \text{N/C}) \][/tex]

Multiply these values together:

[tex]\[ F = 0.638 \times 27.4 \][/tex]

[tex]\[ F = 17.4812 \, \text{N} \][/tex]

The direction of the electric force is determined by the direction of the electric field and the sign of the charge:
- Since the electric field is to the right and the charge is positive, the force will also be to the right.

Therefore, the electric force felt by the charge is:

[tex]\[ F = +17.4812 \, \text{N} \][/tex]

The positive sign indicates that the direction of the force is to the right.
We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.