Looking for trustworthy answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Get immediate answers to your questions from a wide network of experienced professionals on our Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
To determine the equation of the hyperbola with the given vertices and foci, follow these steps:
1. Identify the center of the hyperbola:
The given vertices are [tex]\((0, -8)\)[/tex] and [tex]\((0, 7)\)[/tex]. The center of the hyperbola, which is the midpoint of the vertices, can be found by averaging the y-coordinates of the vertices.
[tex]\[ \text{Center} = \left( 0, \frac{-8 + 7}{2} \right) = \left( 0, -0.5 \right) \][/tex]
2. Find the distance from the center to a vertex, denoted as [tex]\(a\)[/tex]:
The distance [tex]\(a\)[/tex] is the absolute difference between the y-coordinate of a vertex and the center.
[tex]\[ a = \left| 7 - (-0.5) \right| = 7.5 \][/tex]
3. Find the distance from the center to a focus, denoted as [tex]\(c\)[/tex]:
The distance [tex]\(c\)[/tex] is the absolute difference between the y-coordinate of a focus and the center.
[tex]\[ c = \left| 9 - (-0.5) \right| = 9.5 \][/tex]
4. Determine the value of [tex]\(b\)[/tex] using the relationship [tex]\(c^2 = a^2 + b^2\)[/tex]:
[tex]\[ c^2 = a^2 + b^2 \implies b^2 = c^2 - a^2 \][/tex]
Substituting the values for [tex]\(a\)[/tex] and [tex]\(c\)[/tex]:
[tex]\[ b^2 = 9.5^2 - 7.5^2 \][/tex]
[tex]\[ b^2 = 90.25 - 56.25 = 34 \][/tex]
Therefore,
[tex]\[ b = \sqrt{34} \approx 5.830951894845301 \][/tex]
5. Write the equation of the hyperbola:
The standard form of a hyperbola centered at [tex]\((h, k)\)[/tex] with vertical transverse axis is:
[tex]\[ \frac{(y - k)^2}{a^2} - \frac{(x - h)^2}{b^2} = 1 \][/tex]
Here, the center [tex]\((h, k)\)[/tex] is [tex]\((0, -0.5)\)[/tex], [tex]\(a = 7.5\)[/tex], and [tex]\(b \approx 5.830951894845301\)[/tex]. Substituting these values into the equation, we get:
[tex]\[ \frac{(y - (-0.5))^2}{7.5^2} - \frac{(x - 0)^2}{5.830951894845301^2} = 1 \][/tex]
Simplifying further:
[tex]\[ \frac{(y + 0.5)^2}{56.25} - \frac{x^2}{34} = 1 \][/tex]
Thus, the equation of the hyperbola is:
[tex]\[ \frac{(y + 0.5)^2}{56.25} - \frac{x^2}{34} = 1 \][/tex]
1. Identify the center of the hyperbola:
The given vertices are [tex]\((0, -8)\)[/tex] and [tex]\((0, 7)\)[/tex]. The center of the hyperbola, which is the midpoint of the vertices, can be found by averaging the y-coordinates of the vertices.
[tex]\[ \text{Center} = \left( 0, \frac{-8 + 7}{2} \right) = \left( 0, -0.5 \right) \][/tex]
2. Find the distance from the center to a vertex, denoted as [tex]\(a\)[/tex]:
The distance [tex]\(a\)[/tex] is the absolute difference between the y-coordinate of a vertex and the center.
[tex]\[ a = \left| 7 - (-0.5) \right| = 7.5 \][/tex]
3. Find the distance from the center to a focus, denoted as [tex]\(c\)[/tex]:
The distance [tex]\(c\)[/tex] is the absolute difference between the y-coordinate of a focus and the center.
[tex]\[ c = \left| 9 - (-0.5) \right| = 9.5 \][/tex]
4. Determine the value of [tex]\(b\)[/tex] using the relationship [tex]\(c^2 = a^2 + b^2\)[/tex]:
[tex]\[ c^2 = a^2 + b^2 \implies b^2 = c^2 - a^2 \][/tex]
Substituting the values for [tex]\(a\)[/tex] and [tex]\(c\)[/tex]:
[tex]\[ b^2 = 9.5^2 - 7.5^2 \][/tex]
[tex]\[ b^2 = 90.25 - 56.25 = 34 \][/tex]
Therefore,
[tex]\[ b = \sqrt{34} \approx 5.830951894845301 \][/tex]
5. Write the equation of the hyperbola:
The standard form of a hyperbola centered at [tex]\((h, k)\)[/tex] with vertical transverse axis is:
[tex]\[ \frac{(y - k)^2}{a^2} - \frac{(x - h)^2}{b^2} = 1 \][/tex]
Here, the center [tex]\((h, k)\)[/tex] is [tex]\((0, -0.5)\)[/tex], [tex]\(a = 7.5\)[/tex], and [tex]\(b \approx 5.830951894845301\)[/tex]. Substituting these values into the equation, we get:
[tex]\[ \frac{(y - (-0.5))^2}{7.5^2} - \frac{(x - 0)^2}{5.830951894845301^2} = 1 \][/tex]
Simplifying further:
[tex]\[ \frac{(y + 0.5)^2}{56.25} - \frac{x^2}{34} = 1 \][/tex]
Thus, the equation of the hyperbola is:
[tex]\[ \frac{(y + 0.5)^2}{56.25} - \frac{x^2}{34} = 1 \][/tex]
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.