Welcome to Westonci.ca, your ultimate destination for finding answers to a wide range of questions from experts. Explore in-depth answers to your questions from a knowledgeable community of experts across different fields. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.
Sagot :
To determine the equation of the hyperbola with the given vertices and foci, follow these steps:
1. Identify the center of the hyperbola:
The given vertices are [tex]\((0, -8)\)[/tex] and [tex]\((0, 7)\)[/tex]. The center of the hyperbola, which is the midpoint of the vertices, can be found by averaging the y-coordinates of the vertices.
[tex]\[ \text{Center} = \left( 0, \frac{-8 + 7}{2} \right) = \left( 0, -0.5 \right) \][/tex]
2. Find the distance from the center to a vertex, denoted as [tex]\(a\)[/tex]:
The distance [tex]\(a\)[/tex] is the absolute difference between the y-coordinate of a vertex and the center.
[tex]\[ a = \left| 7 - (-0.5) \right| = 7.5 \][/tex]
3. Find the distance from the center to a focus, denoted as [tex]\(c\)[/tex]:
The distance [tex]\(c\)[/tex] is the absolute difference between the y-coordinate of a focus and the center.
[tex]\[ c = \left| 9 - (-0.5) \right| = 9.5 \][/tex]
4. Determine the value of [tex]\(b\)[/tex] using the relationship [tex]\(c^2 = a^2 + b^2\)[/tex]:
[tex]\[ c^2 = a^2 + b^2 \implies b^2 = c^2 - a^2 \][/tex]
Substituting the values for [tex]\(a\)[/tex] and [tex]\(c\)[/tex]:
[tex]\[ b^2 = 9.5^2 - 7.5^2 \][/tex]
[tex]\[ b^2 = 90.25 - 56.25 = 34 \][/tex]
Therefore,
[tex]\[ b = \sqrt{34} \approx 5.830951894845301 \][/tex]
5. Write the equation of the hyperbola:
The standard form of a hyperbola centered at [tex]\((h, k)\)[/tex] with vertical transverse axis is:
[tex]\[ \frac{(y - k)^2}{a^2} - \frac{(x - h)^2}{b^2} = 1 \][/tex]
Here, the center [tex]\((h, k)\)[/tex] is [tex]\((0, -0.5)\)[/tex], [tex]\(a = 7.5\)[/tex], and [tex]\(b \approx 5.830951894845301\)[/tex]. Substituting these values into the equation, we get:
[tex]\[ \frac{(y - (-0.5))^2}{7.5^2} - \frac{(x - 0)^2}{5.830951894845301^2} = 1 \][/tex]
Simplifying further:
[tex]\[ \frac{(y + 0.5)^2}{56.25} - \frac{x^2}{34} = 1 \][/tex]
Thus, the equation of the hyperbola is:
[tex]\[ \frac{(y + 0.5)^2}{56.25} - \frac{x^2}{34} = 1 \][/tex]
1. Identify the center of the hyperbola:
The given vertices are [tex]\((0, -8)\)[/tex] and [tex]\((0, 7)\)[/tex]. The center of the hyperbola, which is the midpoint of the vertices, can be found by averaging the y-coordinates of the vertices.
[tex]\[ \text{Center} = \left( 0, \frac{-8 + 7}{2} \right) = \left( 0, -0.5 \right) \][/tex]
2. Find the distance from the center to a vertex, denoted as [tex]\(a\)[/tex]:
The distance [tex]\(a\)[/tex] is the absolute difference between the y-coordinate of a vertex and the center.
[tex]\[ a = \left| 7 - (-0.5) \right| = 7.5 \][/tex]
3. Find the distance from the center to a focus, denoted as [tex]\(c\)[/tex]:
The distance [tex]\(c\)[/tex] is the absolute difference between the y-coordinate of a focus and the center.
[tex]\[ c = \left| 9 - (-0.5) \right| = 9.5 \][/tex]
4. Determine the value of [tex]\(b\)[/tex] using the relationship [tex]\(c^2 = a^2 + b^2\)[/tex]:
[tex]\[ c^2 = a^2 + b^2 \implies b^2 = c^2 - a^2 \][/tex]
Substituting the values for [tex]\(a\)[/tex] and [tex]\(c\)[/tex]:
[tex]\[ b^2 = 9.5^2 - 7.5^2 \][/tex]
[tex]\[ b^2 = 90.25 - 56.25 = 34 \][/tex]
Therefore,
[tex]\[ b = \sqrt{34} \approx 5.830951894845301 \][/tex]
5. Write the equation of the hyperbola:
The standard form of a hyperbola centered at [tex]\((h, k)\)[/tex] with vertical transverse axis is:
[tex]\[ \frac{(y - k)^2}{a^2} - \frac{(x - h)^2}{b^2} = 1 \][/tex]
Here, the center [tex]\((h, k)\)[/tex] is [tex]\((0, -0.5)\)[/tex], [tex]\(a = 7.5\)[/tex], and [tex]\(b \approx 5.830951894845301\)[/tex]. Substituting these values into the equation, we get:
[tex]\[ \frac{(y - (-0.5))^2}{7.5^2} - \frac{(x - 0)^2}{5.830951894845301^2} = 1 \][/tex]
Simplifying further:
[tex]\[ \frac{(y + 0.5)^2}{56.25} - \frac{x^2}{34} = 1 \][/tex]
Thus, the equation of the hyperbola is:
[tex]\[ \frac{(y + 0.5)^2}{56.25} - \frac{x^2}{34} = 1 \][/tex]
We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.