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(c) Solve the equation [tex]\frac{2x}{5} = 4[/tex].

Value of the variable: [tex]x = 10[/tex].


Sagot :

Let's verify if [tex]\( x = 15 \)[/tex] is a solution to the equation [tex]\( \frac{2x}{5} = 4 \)[/tex].

1. Substitute [tex]\( x = 15 \)[/tex] into the equation:

[tex]\[ \frac{2 \cdot 15}{5} \][/tex]

2. Perform the multiplication in the numerator:

[tex]\[ 2 \cdot 15 = 30 \][/tex]

3. Divide the result by 5:

[tex]\[ \frac{30}{5} = 6 \][/tex]

Thus, the left side of the equation becomes 6.

4. Compare this result to the right side of the original equation:

The right side of the equation is given as 4.

5. Conclusion:

Since [tex]\( 6 \)[/tex] (left side) does not equal [tex]\( 4 \)[/tex] (right side), the equation [tex]\( \frac{2x}{5} = 4 \)[/tex] is NOT satisfied when [tex]\( x = 15 \)[/tex].

Therefore, [tex]\( x = 15 \)[/tex] is not a solution to the equation [tex]\( \frac{2x}{5} = 4 \)[/tex].
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