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A train traveling at 60 km/h leaves a station at 8:00 AM. Another train traveling at 80 km/h leaves the same station at 10:00 AM in the same direction. At what time will the second train catch up with the first train?
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A Train Traveling At 60 Kmh Leaves A Station At 800 AM Another Train Traveling At 80 Kmh Leaves The Same Station At 1000 AM In The Same Direction At What Time W class=

Sagot :

Answer: 4:00 PM

Step-by-step explanation:

Given:

First Train

   60 km/hr at 8:00 AM

Second Train
    80 km/hr at 10 AM

Required:

    Time at which the 2nd train catches up with the first one.

Solution:

    For the first train it has:

Speed = 60 km/hr

Started 2 hours earlier

Distance covered then is (60 km/hr) x (2 hrs) = 120 km

Therefore the first train has already covered 120 km ahead of the second train

Then take the difference of the speeds of both train,

(80 - 60) km/hr = 20 km/hr

Solving for the time needed for the second train to catch,

(120 km) / (20 km / hr) = 6 hrs

This means that the 2nd train needs 6 hrs to catch up with the first one. If it departed at 10:00 AM, then adding 6 hrs forward would be 16:00 or 4:00 PM

semsee45

Answer:

4:00 PM

Step-by-step explanation:

To determine when the second train will catch up with the first train, we need to calculate the time it takes for the second train to cover the distance that the first train has already traveled.

Begin by calculating the head start of the first train. Since the first train leaves two hours before the second train and travels at a speed of 60 km/h, the distance covered by the first train in those first two hours is:

[tex]\text{Head start distance}=60 \text{ km/h} \times 2 \text{ hours} = 120 \text{ km}[/tex]

Next, determine the relative speed between the two trains. Since both trains are traveling in the same direction, the relative speed is the difference in their speeds:

[tex]\text{Relative Speed}=80 \text{ km/h} - 60 \text{ km/h} = 20 \text{ km/h}[/tex]

To find out how long it takes for the second train to catch up with the first train, divide the head start distance by the relative speed:

[tex]\text{Time to catch up}=\dfrac{120 \text{ km}}{20 \text{ km/h}} = 6 \text{ hours}[/tex]

Since the second train leaves at 10:00 AM and takes 6 hours to catch up with the first train, the second train will catch up with the first train at:

[tex]10:00\text{ AM}+6\text{ hours}=4:00\text{ PM}[/tex]

Therefore, the second train will catch up with the first train at 4:00 PM.

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