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Sagot :
To convert the number [tex]\(6.035 \times 10^{-4}\)[/tex] to an ordinary decimal number, follow these steps:
### Step-by-Step Conversion:
1. Identify the Scientific Notation:
- The given number is in scientific notation, which is of the form [tex]\(a \times 10^b\)[/tex], where [tex]\(a = 6.035\)[/tex] and [tex]\(b = -4\)[/tex].
2. Understand the Exponent:
- The exponent [tex]\(-4\)[/tex] indicates that we need to move the decimal point in [tex]\(6.035\)[/tex] four places to the left because the exponent is negative.
3. Move the Decimal Point:
- Starting with [tex]\(6.035\)[/tex], we will move the decimal point four places to the left.
- Moving one place to the left: [tex]\(0.6035\)[/tex] (one place)
- Moving another place to the left: [tex]\(0.06035\)[/tex] (two places)
- Moving another place to the left: [tex]\(0.006035\)[/tex] (three places)
- Moving the fourth place to the left: [tex]\(0.0006035\)[/tex]
4. Final Result:
- After moving the decimal point four places to the left, the ordinary number is [tex]\(0.0006035\)[/tex].
### Answer:
Therefore, [tex]\(6.035 \times 10^{-4}\)[/tex] as an ordinary number is [tex]\(\boxed{0.0006035}\)[/tex].
### Step-by-Step Conversion:
1. Identify the Scientific Notation:
- The given number is in scientific notation, which is of the form [tex]\(a \times 10^b\)[/tex], where [tex]\(a = 6.035\)[/tex] and [tex]\(b = -4\)[/tex].
2. Understand the Exponent:
- The exponent [tex]\(-4\)[/tex] indicates that we need to move the decimal point in [tex]\(6.035\)[/tex] four places to the left because the exponent is negative.
3. Move the Decimal Point:
- Starting with [tex]\(6.035\)[/tex], we will move the decimal point four places to the left.
- Moving one place to the left: [tex]\(0.6035\)[/tex] (one place)
- Moving another place to the left: [tex]\(0.06035\)[/tex] (two places)
- Moving another place to the left: [tex]\(0.006035\)[/tex] (three places)
- Moving the fourth place to the left: [tex]\(0.0006035\)[/tex]
4. Final Result:
- After moving the decimal point four places to the left, the ordinary number is [tex]\(0.0006035\)[/tex].
### Answer:
Therefore, [tex]\(6.035 \times 10^{-4}\)[/tex] as an ordinary number is [tex]\(\boxed{0.0006035}\)[/tex].
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