Answered

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Let Q₁ be the sample mean and Q₂ the sample standard deviation of the numbers listed below.
0.8, 9.66, 4.17, 2.19, 12.03, 19.87, −2.49, 14.23, 10.64, −6.56, 1.19, 10.63, 8.92, 9.14, 18.33,−6.84, 10.57, −3.03, 12.26, 12.04
Let Q = ln(3 + |Q₁| + 2|Q₂|). Then T = 5 sin²(100Q) satisfies:—

(A) 0 ≤ T < 1.
(B) 1 ≤ T < 2.
(C) 2 ≤ T < 3.
(D) 3 ≤ T < 4.
(E) 4 ≤ T ≤ 5

Sagot :

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