Westonci.ca is the ultimate Q&A platform, offering detailed and reliable answers from a knowledgeable community. Explore a wealth of knowledge from professionals across different disciplines on our comprehensive platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
To find the solutions to the equation [tex]\(x^2 = 12\)[/tex], let's go through the solution step-by-step:
1. Understanding the Equation:
The equation [tex]\(x^2 = 12\)[/tex] expresses that [tex]\(x\)[/tex] squared is equal to 12. We need to find the values of [tex]\(x\)[/tex] that satisfy this equation.
2. Solving for [tex]\(x\)[/tex]:
We can solve the equation by taking the square root of both sides. Remember that taking the square root of both sides will yield both the positive and negative roots.
[tex]\[ x = \pm \sqrt{12} \][/tex]
3. Simplifying [tex]\(\sqrt{12}\)[/tex]:
Next, we simplify [tex]\(\sqrt{12}\)[/tex]. We do this by factoring 12 into its prime components:
[tex]\[ 12 = 4 \times 3 \quad \text{and} \quad 4 = 2^2 \][/tex]
Therefore,
[tex]\[ \sqrt{12} = \sqrt{4 \times 3} = \sqrt{4} \times \sqrt{3} = 2\sqrt{3} \][/tex]
4. General Solution:
Thus, the solutions to the equation [tex]\(x^2 = 12\)[/tex] are:
[tex]\[ x = \pm 2\sqrt{3} \][/tex]
5. Matching with the Options Given:
Now, we compare these solutions with the options provided:
A. [tex]\(x = \pm 2 \sqrt{6}\)[/tex]
B. [tex]\(x = \pm 6 \sqrt{2}\)[/tex]
C. [tex]\(x = \pm 3 \sqrt{2}\)[/tex]
D. [tex]\(x = \pm 2 \sqrt{3}\)[/tex]
From our work, we determined that the solutions are:
[tex]\[ x = \pm 2\sqrt{3} \][/tex]
These match exactly with Option D:
[tex]\[ x = \pm 2 \sqrt{3} \][/tex]
So, the correct answer is Option D: [tex]\(x = \pm 2\sqrt{3}\)[/tex].
1. Understanding the Equation:
The equation [tex]\(x^2 = 12\)[/tex] expresses that [tex]\(x\)[/tex] squared is equal to 12. We need to find the values of [tex]\(x\)[/tex] that satisfy this equation.
2. Solving for [tex]\(x\)[/tex]:
We can solve the equation by taking the square root of both sides. Remember that taking the square root of both sides will yield both the positive and negative roots.
[tex]\[ x = \pm \sqrt{12} \][/tex]
3. Simplifying [tex]\(\sqrt{12}\)[/tex]:
Next, we simplify [tex]\(\sqrt{12}\)[/tex]. We do this by factoring 12 into its prime components:
[tex]\[ 12 = 4 \times 3 \quad \text{and} \quad 4 = 2^2 \][/tex]
Therefore,
[tex]\[ \sqrt{12} = \sqrt{4 \times 3} = \sqrt{4} \times \sqrt{3} = 2\sqrt{3} \][/tex]
4. General Solution:
Thus, the solutions to the equation [tex]\(x^2 = 12\)[/tex] are:
[tex]\[ x = \pm 2\sqrt{3} \][/tex]
5. Matching with the Options Given:
Now, we compare these solutions with the options provided:
A. [tex]\(x = \pm 2 \sqrt{6}\)[/tex]
B. [tex]\(x = \pm 6 \sqrt{2}\)[/tex]
C. [tex]\(x = \pm 3 \sqrt{2}\)[/tex]
D. [tex]\(x = \pm 2 \sqrt{3}\)[/tex]
From our work, we determined that the solutions are:
[tex]\[ x = \pm 2\sqrt{3} \][/tex]
These match exactly with Option D:
[tex]\[ x = \pm 2 \sqrt{3} \][/tex]
So, the correct answer is Option D: [tex]\(x = \pm 2\sqrt{3}\)[/tex].
We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.