Discover the answers to your questions at Westonci.ca, where experts share their knowledge and insights with you. Experience the convenience of finding accurate answers to your questions from knowledgeable professionals on our platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
To find the rate of acceleration, we can use the kinematic equation that relates initial velocity u, final velocity v, acceleration a, and distance s:
[tex]v^2=u^2+2as[/tex]
Given:
- Initial velocity, u = 5.5 m/s
- Final velocity, v = 9.0 m/s
- Distance, s = 32 m
We need to solve for acceleration a. Rearranging the equation for a:
[tex]a=(v^2-u^2)/2s[/tex]
Substituting the given values:
[tex]\[ a = \frac{(9.0 \, \text{m/s})^2 - (5.5 \, \text{m/s})^2}{2 \times 32 \, \text{m}} \][/tex]
Let's calculate it:
[tex]\[ a = \frac{81 - 30.25}{64} \]\[ a = \frac{50.75}{64} \]\[ a \approx 0.793 \, \text{m/s}^2 \][/tex]
So, the rate at which the boat is accelerating is approximately [tex]\( 0.793 \, \text{m/s}^2 \).[/tex]
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.
