Discover the answers you need at Westonci.ca, a dynamic Q&A platform where knowledge is shared freely by a community of experts. Experience the convenience of getting accurate answers to your questions from a dedicated community of professionals. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
To solve the problem of finding the equivalent formula for the circumference of a circle given the options, we first need to understand the basic relationships involving the radius [tex]\( r \)[/tex], diameter [tex]\( d \)[/tex], and circumference [tex]\( C \)[/tex].
1. Recall the Formula for Circumference:
The circumference [tex]\( C \)[/tex] of a circle is given by:
[tex]\[ C = 2\pi r \][/tex]
2. Relationship Between Radius and Diameter:
The diameter [tex]\( d \)[/tex] of a circle is twice the radius:
[tex]\[ d = 2r \][/tex]
3. Rewriting Circumference in Terms of Diameter:
Substitute [tex]\( d = 2r \)[/tex] into the circumference formula:
[tex]\[ C = 2\pi r = \pi d \][/tex]
This tells us that the circumference can also be expressed as:
[tex]\[ C=\pi d \][/tex]
4. Examine the Options:
- Option A: [tex]\( C = \pi d \)[/tex]
This matches our derived formula exactly, so this is correct.
- Option B: [tex]\( C = \pi d r \)[/tex]
This formulation does not match the derived formula. To check this, if we plug in specific values where [tex]\( r = 1 \)[/tex] and [tex]\( d = 2r = 2 \)[/tex]:
[tex]\[ C = \pi \cdot 2 \cdot 1 = 2\pi, \][/tex]
but [tex]\( C = 2\pi r = \pi d \)[/tex]. This is incorrect since it introduces an unnecessary multiplication by [tex]\( r \)[/tex].
- Option C: [tex]\( C = \pi r^2 \)[/tex]
This is the formula for the area of a circle, not the circumference. Hence, this is incorrect. For [tex]\( r = 1 \)[/tex]:
[tex]\[ \pi r^2 = \pi \cdot 1^2 = \pi \][/tex]
giving us the area, not the circumference.
- Option D: [tex]\( C = 2 \pi d \)[/tex]
Using [tex]\( d = 2r \)[/tex], we get:
[tex]\[ C = 2 \pi \cdot 2r = 4 \pi r \][/tex]
which does not simplify into the form [tex]\( 2 \pi r \)[/tex]. Therefore, this is also incorrect.
5. Verify with Given Values:
By evaluating with a radius of [tex]\( r = 1 \)[/tex] unit, we calculate the diameter:
[tex]\[ d = 2 \times 1 = 2 \][/tex]
Calculate the actual circumference which is:
[tex]\[ C = 2 \pi \cdot 1 = 2\pi \approx 6.2831853072 \][/tex]
Check each option:
- [tex]\( A = \pi \cdot 2 \approx 6.2831853072 \)[/tex]
- [tex]\( B = \pi \cdot 2 \cdot 1 \approx 6.2831853072 \)[/tex]
- [tex]\( C = \pi \cdot 1^2 \approx 3.1415926536 \)[/tex]
- [tex]\( D = 2 \pi \cdot 2 \approx 12.5663706144 \)[/tex]
This confirms the correct option is:
Option A: [tex]\( C = \pi d \)[/tex]
1. Recall the Formula for Circumference:
The circumference [tex]\( C \)[/tex] of a circle is given by:
[tex]\[ C = 2\pi r \][/tex]
2. Relationship Between Radius and Diameter:
The diameter [tex]\( d \)[/tex] of a circle is twice the radius:
[tex]\[ d = 2r \][/tex]
3. Rewriting Circumference in Terms of Diameter:
Substitute [tex]\( d = 2r \)[/tex] into the circumference formula:
[tex]\[ C = 2\pi r = \pi d \][/tex]
This tells us that the circumference can also be expressed as:
[tex]\[ C=\pi d \][/tex]
4. Examine the Options:
- Option A: [tex]\( C = \pi d \)[/tex]
This matches our derived formula exactly, so this is correct.
- Option B: [tex]\( C = \pi d r \)[/tex]
This formulation does not match the derived formula. To check this, if we plug in specific values where [tex]\( r = 1 \)[/tex] and [tex]\( d = 2r = 2 \)[/tex]:
[tex]\[ C = \pi \cdot 2 \cdot 1 = 2\pi, \][/tex]
but [tex]\( C = 2\pi r = \pi d \)[/tex]. This is incorrect since it introduces an unnecessary multiplication by [tex]\( r \)[/tex].
- Option C: [tex]\( C = \pi r^2 \)[/tex]
This is the formula for the area of a circle, not the circumference. Hence, this is incorrect. For [tex]\( r = 1 \)[/tex]:
[tex]\[ \pi r^2 = \pi \cdot 1^2 = \pi \][/tex]
giving us the area, not the circumference.
- Option D: [tex]\( C = 2 \pi d \)[/tex]
Using [tex]\( d = 2r \)[/tex], we get:
[tex]\[ C = 2 \pi \cdot 2r = 4 \pi r \][/tex]
which does not simplify into the form [tex]\( 2 \pi r \)[/tex]. Therefore, this is also incorrect.
5. Verify with Given Values:
By evaluating with a radius of [tex]\( r = 1 \)[/tex] unit, we calculate the diameter:
[tex]\[ d = 2 \times 1 = 2 \][/tex]
Calculate the actual circumference which is:
[tex]\[ C = 2 \pi \cdot 1 = 2\pi \approx 6.2831853072 \][/tex]
Check each option:
- [tex]\( A = \pi \cdot 2 \approx 6.2831853072 \)[/tex]
- [tex]\( B = \pi \cdot 2 \cdot 1 \approx 6.2831853072 \)[/tex]
- [tex]\( C = \pi \cdot 1^2 \approx 3.1415926536 \)[/tex]
- [tex]\( D = 2 \pi \cdot 2 \approx 12.5663706144 \)[/tex]
This confirms the correct option is:
Option A: [tex]\( C = \pi d \)[/tex]
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.