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A species of fly has two alleles for the length of their legs. The allele for long legs is dominant and is represented by [tex]$p$[/tex]. The allele for short legs is recessive and is represented by [tex]$q$[/tex]. If 21 out of 100 organisms have short legs, what is [tex][tex]$p$[/tex][/tex]?

Given:
[tex]p^2 + 2pq + q^2 = 1[/tex]

A. 0.79
B. 0.46
C. 0.54
D. 0.21


Sagot :

To determine the value of [tex]\( p \)[/tex], given that the allele for short legs (recessive) is represented by [tex]\( q \)[/tex] and 21 out of 100 organisms have short legs, we start with the information provided.

1. Determine [tex]\( q \)[/tex]:
Since 21 out of 100 organisms have short legs, this corresponds to the recessive phenotype. The frequency of the recessive allele ([tex]\( q \)[/tex]) can be represented as:
[tex]\[ q = \frac{21}{100} = 0.21 \][/tex]

2. Calculate [tex]\( p \)[/tex]:
We know that the sum of the frequencies of the dominant allele ([tex]\( p \)[/tex]) and the recessive allele ([tex]\( q \)[/tex]) must equal 1:
[tex]\[ p + q = 1 \][/tex]
Given [tex]\( q = 0.21 \)[/tex]:
[tex]\[ p = 1 - q = 1 - 0.21 = 0.79 \][/tex]

After determining [tex]\( p \)[/tex], we verify we have utilized the equation [tex]\( p + q = 1 \)[/tex]. Since [tex]\( p = 0.79 \)[/tex] and [tex]\( q = 0.21 \)[/tex], adding these values should yield:
[tex]\[ p + q = 0.79 + 0.21 = 1 \][/tex]

Therefore, the correct value of [tex]\( p \)[/tex] is [tex]\( 0.79 \)[/tex].

Thus, the answer is:
[tex]\[ \boxed{0.79} \][/tex]