Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Experience the ease of finding accurate answers to your questions from a knowledgeable community of professionals. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
To determine the new gravitational force between the Earth and the satellite when the distance is increased by a factor of 4, follow these steps:
1. Understand the gravitational force law:
The gravitational force between two masses is inversely proportional to the square of the distance between them. This means if the distance is [tex]\( d \)[/tex], the gravitational force [tex]\( F \)[/tex] is proportional to [tex]\( \frac{1}{d^2} \)[/tex].
2. Original force and distance information:
The original gravitational force between the Earth and the satellite is 243 N, at some initial distance [tex]\( d \)[/tex].
3. Effect of increasing the distance by a factor of 4:
If the distance increases to 4 times the original distance (i.e., [tex]\( 4d \)[/tex]), then according to the inverse square law, the force will be reduced by a factor of [tex]\( (4)^2 \)[/tex].
4. Calculate the factor reduction:
[tex]\[ \text{Reduction factor} = 4^2 = 16 \][/tex]
5. Determine the new force:
The new force is obtained by dividing the original force by this factor:
[tex]\[ \text{New Force} = \frac{\text{Original Force}}{\text{Reduction Factor}} = \frac{243}{16} \][/tex]
6. Perform the division to find the precise force:
[tex]\[ \text{New Force} = \frac{243}{16} \approx 15.1875 \][/tex]
7. Round the result to the nearest whole number:
We round 15.1875 to the nearest whole number, which gives 15.
Conclusion:
The new gravitational force between the Earth and the satellite, when it is moved to 4 times the original distance, is approximately [tex]\( 15 \)[/tex] N.
1. Understand the gravitational force law:
The gravitational force between two masses is inversely proportional to the square of the distance between them. This means if the distance is [tex]\( d \)[/tex], the gravitational force [tex]\( F \)[/tex] is proportional to [tex]\( \frac{1}{d^2} \)[/tex].
2. Original force and distance information:
The original gravitational force between the Earth and the satellite is 243 N, at some initial distance [tex]\( d \)[/tex].
3. Effect of increasing the distance by a factor of 4:
If the distance increases to 4 times the original distance (i.e., [tex]\( 4d \)[/tex]), then according to the inverse square law, the force will be reduced by a factor of [tex]\( (4)^2 \)[/tex].
4. Calculate the factor reduction:
[tex]\[ \text{Reduction factor} = 4^2 = 16 \][/tex]
5. Determine the new force:
The new force is obtained by dividing the original force by this factor:
[tex]\[ \text{New Force} = \frac{\text{Original Force}}{\text{Reduction Factor}} = \frac{243}{16} \][/tex]
6. Perform the division to find the precise force:
[tex]\[ \text{New Force} = \frac{243}{16} \approx 15.1875 \][/tex]
7. Round the result to the nearest whole number:
We round 15.1875 to the nearest whole number, which gives 15.
Conclusion:
The new gravitational force between the Earth and the satellite, when it is moved to 4 times the original distance, is approximately [tex]\( 15 \)[/tex] N.
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.