Westonci.ca is the best place to get answers to your questions, provided by a community of experienced and knowledgeable experts. Discover reliable solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.
Sagot :
To determine the new gravitational force between the Earth and the satellite when the distance is increased by a factor of 4, follow these steps:
1. Understand the gravitational force law:
The gravitational force between two masses is inversely proportional to the square of the distance between them. This means if the distance is [tex]\( d \)[/tex], the gravitational force [tex]\( F \)[/tex] is proportional to [tex]\( \frac{1}{d^2} \)[/tex].
2. Original force and distance information:
The original gravitational force between the Earth and the satellite is 243 N, at some initial distance [tex]\( d \)[/tex].
3. Effect of increasing the distance by a factor of 4:
If the distance increases to 4 times the original distance (i.e., [tex]\( 4d \)[/tex]), then according to the inverse square law, the force will be reduced by a factor of [tex]\( (4)^2 \)[/tex].
4. Calculate the factor reduction:
[tex]\[ \text{Reduction factor} = 4^2 = 16 \][/tex]
5. Determine the new force:
The new force is obtained by dividing the original force by this factor:
[tex]\[ \text{New Force} = \frac{\text{Original Force}}{\text{Reduction Factor}} = \frac{243}{16} \][/tex]
6. Perform the division to find the precise force:
[tex]\[ \text{New Force} = \frac{243}{16} \approx 15.1875 \][/tex]
7. Round the result to the nearest whole number:
We round 15.1875 to the nearest whole number, which gives 15.
Conclusion:
The new gravitational force between the Earth and the satellite, when it is moved to 4 times the original distance, is approximately [tex]\( 15 \)[/tex] N.
1. Understand the gravitational force law:
The gravitational force between two masses is inversely proportional to the square of the distance between them. This means if the distance is [tex]\( d \)[/tex], the gravitational force [tex]\( F \)[/tex] is proportional to [tex]\( \frac{1}{d^2} \)[/tex].
2. Original force and distance information:
The original gravitational force between the Earth and the satellite is 243 N, at some initial distance [tex]\( d \)[/tex].
3. Effect of increasing the distance by a factor of 4:
If the distance increases to 4 times the original distance (i.e., [tex]\( 4d \)[/tex]), then according to the inverse square law, the force will be reduced by a factor of [tex]\( (4)^2 \)[/tex].
4. Calculate the factor reduction:
[tex]\[ \text{Reduction factor} = 4^2 = 16 \][/tex]
5. Determine the new force:
The new force is obtained by dividing the original force by this factor:
[tex]\[ \text{New Force} = \frac{\text{Original Force}}{\text{Reduction Factor}} = \frac{243}{16} \][/tex]
6. Perform the division to find the precise force:
[tex]\[ \text{New Force} = \frac{243}{16} \approx 15.1875 \][/tex]
7. Round the result to the nearest whole number:
We round 15.1875 to the nearest whole number, which gives 15.
Conclusion:
The new gravitational force between the Earth and the satellite, when it is moved to 4 times the original distance, is approximately [tex]\( 15 \)[/tex] N.
We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.