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Sagot :
Answer:
(a) 2 hours , (b) 20 Km per hour , (c) 20 Km from home
Step-by-step explanation:
(a)
The return journey is represented by the line sloping down from left to right on the graph.
The top of the line is 6.00 am
The bottom of the line is 8.00 am
time taken on return journey = 8 - 6 = 2 hours
(b)
average speed is calculated as distance ÷ time
The distance of the journey is 40 Km and time taken is 2 hours , then
average speed = 40 Km ÷ 2 hours = 20 Km per hour
(c)
Each division on the time - axis is 15 minutes
So at 5.30 am the car is 20 Km from home
Answer:
1) The car took 2 hours for the return journey
2) The average speed on return journey was 20 km / h
3) At 5:30 am the car was midway between home and school - 20 km from home and 20 km from the school
Step-by-step explanation:
Looking at the graph we see that the car left at 5:00 am and reached school at 6:00 am which is a 1 hour time of travel for a distance of 40 km
The return trip is also 40 km
For the return trip, the car left at 6:00 am and reached at 8:00 am
Return trip travel time = 8 - 6 = 2 hours
Return trip distance = 40 km
Average speed of return journey = 40 km / 2 hours = 20 km /h
At 5:30 am, looking at the graph, the car was 20 km from home and also 20 km from the school. So it was midway between home and school
Answers
1) The car took 2 hours for the return journey
2) The average speed on return journey was 20 km / h
3) At 5:30 am the car was midway between home and school - 20 km from home and 20 km from the school
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