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Which graph shows the solution set for [tex]$-4.4 \geq 1.6x - 3.6$[/tex]?

A. [Graph A]

B. [Graph B]

C. [Graph C]

D. [Graph D]


Sagot :

Sure, let's solve the given inequality step-by-step:

1. Given inequality:
[tex]\[ -4.4 \geq 1.6x - 3.6 \][/tex]

2. Isolate the term with [tex]\(x\)[/tex]:
[tex]\[ -4.4 + 3.6 \geq 1.6x \][/tex]

3. Simplify the left side:
[tex]\[ -0.8 \geq 1.6x \][/tex]

4. Solve for [tex]\(x\)[/tex] by dividing both sides by 1.6:
[tex]\[ \frac{-0.8}{1.6} \geq x \][/tex]

Simplifying the division:
[tex]\[ -0.5 \geq x \][/tex]
or equivalently:
[tex]\[ x \leq -0.5 \][/tex]

So, the solution to the inequality [tex]\( -4.4 \geq 1.6x - 3.6 \)[/tex] is [tex]\( x \leq -0.5 \)[/tex].

### Graphing the Solution Set

To graph this solution:

1. Draw a number line: Mark the point [tex]\(-0.5\)[/tex] on the number line.
2. Closed circle at [tex]\(-0.5\)[/tex]: Because the inequality includes [tex]\(\leq\)[/tex], [tex]\(-0.5\)[/tex] is part of the solution.
3. Shade to the left of [tex]\(-0.5\)[/tex]: Because [tex]\(x\)[/tex] should be less than or equal to [tex]\(-0.5\)[/tex].

The graph would look like this:

[tex]\[ \begin{array}{cccccccccccccccc} & & & & & & -0.5 && & & & & & & \\ \bullet & \longleftarrow & \longleftarrow & \longleftarrow & \longleftarrow & \longleftarrow & \bullet & \and & & & & & & \end{array} \][/tex]

The darkened arrow to the left indicates that all numbers less than [tex]\(-0.5\)[/tex] are included in the solution set. The closed circle at [tex]\(-0.5\)[/tex] shows that [tex]\(-0.5\)[/tex] itself is also part of the solution.