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The original task seems to be presenting a set of fractions and an addition problem, but it is not coherent. Here is a revised and coherent mathematical expression:

[tex]\[
\frac{1}{5} = \frac{3}{15} \quad \text{and} \quad \frac{2}{3} + (-) =
\][/tex]

This format presents the fractions and the addition problem more clearly. However, the second part still seems incomplete and requires clarification. If the task is meant to solve for an unknown or complete the equation, additional context or information is needed.


Sagot :

Let's solve the given equation step by step.

We start with the equation:

[tex]\[ \frac{1}{5} = \frac{3}{15} + \frac{2}{3} \][/tex]

1. Simplify the fractions if necessary:
- [tex]\(\frac{1}{5}\)[/tex] is already in its simplest form.
- [tex]\(\frac{3}{15}\)[/tex] can also be simplified. [tex]\(\frac{3}{15}\)[/tex] simplifies to [tex]\(\frac{1}{5}\)[/tex].

2. Calculate the decimal equivalents:
- The decimal equivalent of [tex]\(\frac{1}{5}\)[/tex] is [tex]\(0.2\)[/tex].
- The decimal equivalent of [tex]\(\frac{3}{15}\)[/tex] (or [tex]\(\frac{1}{5}\)[/tex] simplified) is [tex]\(0.2\)[/tex].
- The decimal equivalent of [tex]\(\frac{2}{3}\)[/tex] is approximately [tex]\(0.6666666666666666\)[/tex].

3. Perform the calculations for each side of the equation:
- The left side of the equation is [tex]\(\frac{1}{5}\)[/tex], which we already found to be [tex]\(0.2\)[/tex].
- The right side of the equation is the sum of [tex]\(\frac{3}{15}\)[/tex] and [tex]\(\frac{2}{3}\)[/tex]. We have:
[tex]\[ \frac{3}{15} + \frac{2}{3} = 0.2 + 0.6666666666666666 = 0.8666666666666667 \][/tex]

4. Conclusion:
- The left side of the equation is [tex]\(0.2\)[/tex].
- The right side of the equation is approximately [tex]\(0.8666666666666667\)[/tex].
- Since [tex]\(0.2 \neq 0.8666666666666667\)[/tex], the given equation [tex]\(\frac{1}{5} = \frac{3}{15} + \frac{2}{3}\)[/tex] does not hold true.

Thus, after breaking down the steps and evaluating each fraction, it is clear that the left side and the right side of the equation are not equal.