Welcome to Westonci.ca, where curiosity meets expertise. Ask any question and receive fast, accurate answers from our knowledgeable community. Get immediate and reliable solutions to your questions from a community of experienced experts on our Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
To find the lower quartile (Q1) of the given data set [tex]\( \{1, 3, 3, 4, 4, 4, 5, 6, 6, 8\} \)[/tex], follow these steps:
1. Organize the Data:
Ensure the data is in ascending order: [tex]\( \{1, 3, 3, 4, 4, 4, 5, 6, 6, 8\} \)[/tex].
2. Determine the Number of Data Points:
The data set contains 10 values.
3. Calculate the Position of the Lower Quartile:
The position of the lower quartile (Q1) is determined using the formula:
[tex]\[ Q1\_position = \frac{(n + 1)}{4} \][/tex]
where [tex]\( n \)[/tex] is the number of data points. For this data set:
[tex]\[ Q1\_position = \frac{(10 + 1)}{4} = \frac{11}{4} = 2.75 \][/tex]
4. Determine the Value of Q1:
Since the position 2.75 is not an integer, we need to interpolate between the second and third data points in the ordered list.
- The 2nd data point is 3.
- The 3rd data point is 3.
To interpolate, we calculate:
[tex]\[ Q1 = \text{lower value} + (\text{fraction} \times \Delta \text{value}) \][/tex]
Here, the lower value is 3 (2nd data point), the fraction part is 0.75 (from 2.75), and the [tex]\(\Delta \text{value}\)[/tex] (difference between the 3rd and 2nd value) is 0.
So, the calculation will be:
[tex]\[ Q1 = 3 + 0.75 \times 0 = 3 \][/tex]
Therefore, the lower quartile (Q1) of the data set is:
[tex]\[ \boxed{3} \][/tex]
1. Organize the Data:
Ensure the data is in ascending order: [tex]\( \{1, 3, 3, 4, 4, 4, 5, 6, 6, 8\} \)[/tex].
2. Determine the Number of Data Points:
The data set contains 10 values.
3. Calculate the Position of the Lower Quartile:
The position of the lower quartile (Q1) is determined using the formula:
[tex]\[ Q1\_position = \frac{(n + 1)}{4} \][/tex]
where [tex]\( n \)[/tex] is the number of data points. For this data set:
[tex]\[ Q1\_position = \frac{(10 + 1)}{4} = \frac{11}{4} = 2.75 \][/tex]
4. Determine the Value of Q1:
Since the position 2.75 is not an integer, we need to interpolate between the second and third data points in the ordered list.
- The 2nd data point is 3.
- The 3rd data point is 3.
To interpolate, we calculate:
[tex]\[ Q1 = \text{lower value} + (\text{fraction} \times \Delta \text{value}) \][/tex]
Here, the lower value is 3 (2nd data point), the fraction part is 0.75 (from 2.75), and the [tex]\(\Delta \text{value}\)[/tex] (difference between the 3rd and 2nd value) is 0.
So, the calculation will be:
[tex]\[ Q1 = 3 + 0.75 \times 0 = 3 \][/tex]
Therefore, the lower quartile (Q1) of the data set is:
[tex]\[ \boxed{3} \][/tex]
Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.