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The data set represents the total number of tuba players in each of 11 different school bands: [tex]$1, 3, 3, 4, 4, 4, 5, 6, 6, 8$[/tex]

What is the lower quartile of the data?

A. 1
B. 3
C. 4
D. 6


Sagot :

To find the lower quartile (Q1) of the given data set [tex]\( \{1, 3, 3, 4, 4, 4, 5, 6, 6, 8\} \)[/tex], follow these steps:

1. Organize the Data:
Ensure the data is in ascending order: [tex]\( \{1, 3, 3, 4, 4, 4, 5, 6, 6, 8\} \)[/tex].

2. Determine the Number of Data Points:
The data set contains 10 values.

3. Calculate the Position of the Lower Quartile:
The position of the lower quartile (Q1) is determined using the formula:

[tex]\[ Q1\_position = \frac{(n + 1)}{4} \][/tex]

where [tex]\( n \)[/tex] is the number of data points. For this data set:

[tex]\[ Q1\_position = \frac{(10 + 1)}{4} = \frac{11}{4} = 2.75 \][/tex]

4. Determine the Value of Q1:
Since the position 2.75 is not an integer, we need to interpolate between the second and third data points in the ordered list.

- The 2nd data point is 3.
- The 3rd data point is 3.

To interpolate, we calculate:

[tex]\[ Q1 = \text{lower value} + (\text{fraction} \times \Delta \text{value}) \][/tex]

Here, the lower value is 3 (2nd data point), the fraction part is 0.75 (from 2.75), and the [tex]\(\Delta \text{value}\)[/tex] (difference between the 3rd and 2nd value) is 0.

So, the calculation will be:

[tex]\[ Q1 = 3 + 0.75 \times 0 = 3 \][/tex]

Therefore, the lower quartile (Q1) of the data set is:

[tex]\[ \boxed{3} \][/tex]