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Susie is visiting China from the U.S. One day she stopped by a market and found a stall selling tomatoes for 14.89 yuan per kilogram. If 1 yuan was worth 0.14 dollars that day, how much did the tomatoes cost in dollars per pound?

First, fill in the two blanks on the left side of the equation using two of the ratios. Then write your answer rounded to the nearest hundredth on the right side of the equation.

\begin{tabular}{|ccc|}
\hline
yuan & dollars & is \\
\hline
m & [tex]$\frac{\square}{\square}$[/tex] & [tex]$\square^a$[/tex] \\
\hline
[tex]$x$[/tex] & 5 \\
\hline
\end{tabular}

Sagot :

Sure, let's walk through the problem step by step.

1. Determine the cost of tomatoes in dollars per kilogram.

We know that the tomatoes cost 14.89 yuan per kilogram, and the exchange rate is 1 yuan = 0.14 dollars.

So, the first conversion is from yuan to dollars:
[tex]\[ \text{Price in dollars per kilogram} = \text{Price in yuan per kilogram} \times \text{Exchange rate} \][/tex]

2. Convert yuan per kilogram to dollars per kilogram:

[tex]\[ 14.89 \, \text{yuan/kg} \times 0.14 \, \text{dollars/yuan} = 2.0846 \, \text{dollars/kg} \][/tex]

3. Convert the cost from dollars per kilogram to dollars per pound.

The conversion factor between kilograms and pounds is:
[tex]\[ 1 \, \text{kg} = 2.20462 \, \text{lb} \][/tex]

Therefore, inverting the conversion to find how many kilograms in a pound gives us:
[tex]\[ 1 \, \text{lb} = \frac{1 \, \text{kg}}{2.20462} \][/tex]

4. Convert dollars per kilogram to dollars per pound:

[tex]\[ \text{Price in dollars per pound} = \frac{\text{Price in dollars per kilogram}}{2.20462} \][/tex]

[tex]\[ \text{Price in dollars per pound} = \frac{2.0846 \, \text{dollars/kg}}{2.20462 \, \text{kg/lb}} \][/tex]

[tex]\[ \text{Price in dollars per pound} = 0.9466 \, \text{dollars/lb} \][/tex]

5. Round the result to the nearest hundredth:

[tex]\[ 0.9466 \, \text{rounds to} \, 0.95 \, \text{dollars/lb} \][/tex]

So, the cost of the tomatoes in dollars per pound is 0.95.

Now, filling in the blanks in your tabular representation, we get:
[tex]\[ \begin{tabular}{|ccc|} \hline yuan & dollars & is \\ m & $\frac{0.14}{2.20462}$ & $0.95$ \\ $x$ & 5 \end{tabular} \][/tex]

And that's the fully detailed solution!